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∙ 12y ago1 joule = 2.39 X 10-4 kcal
65-30 = 35 degrees
1 kcal = 1 degree kg
35 degrees X 0.5 kg / 2.39 X 10-4 kcal/joulle = 73222 joules
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∙ 12y agoq(joules) = mass * specific heat * change in temperature ( 8 kg = 8000 grams ) q = (8000 grams H2O)(4.180 J/gC)(70o C - 20o C) = 1.7 X 106 joules ============
E = mass x specific heat x Δ°T Δ°T = new temperature - original temperature where Δ°T is equal to temperature change (Celsius in this case). The specific heat of Al is 0.900 J/g°C. Before we proceed to find the quantity of heat in joules, we must first find the temperature change. To calculate the temperature change, we must subtract the original temperature from the new temperature. Δ°T = 50°C - 25°C = 25°C In order to find the quantity of heat (joules), we must multiply mass, specific heat, and the temperature change (calculated above). E = 40.0g x 0.900 J/g°C x 25°C = 900 Joules or 9.0 x 102 Joules
The energy required to raise the temperature of water depends on the atmospheric pressure as well as the starting temperature. At a pressure of one atmosphere, the amount of energy required to raise the temperature of water from 0 deg C to 100 deg C (32 to 212 deg F) is 4.19 joules per gram. At 4 deg C, (39.2 deg F) it is approx 4.204 joules per gram per deg C. That is 4.204/1.8 = 2.33555... recurring joules per gram per deg F and so, for a kilogram, the energy required is 2335.55... joules.
The specific heat of air at 0 degrees Celsius is 1.01 Joules per gram or J/g. The specific heat of a substance is defined as the quantity of heat per unit mass needed to raise its temperature by one degree Celsius.
Heat energy is measured in joules (newton-meters), which are also a unit of work.The calorie is a mostly-superseded unit equal to 4.2 joules, while the "food energy" calorie is actually a kilocalorie (1000 calories).Units of temperature are a related value, indicating the relative contained heat energy. The units of temperature are the kelvin / degree Celsius and the different interval, the degree Fahrenheit. Classically, adding 1 mean calorie of heat energy would raise the temperature of 1 gram of water by 1 degree Celsius.
q(joules) = mass * specific heat * change in temperature ( 8 kg = 8000 grams ) q = (8000 grams H2O)(4.180 J/gC)(70o C - 20o C) = 1.7 X 106 joules ============
The amount of energy required to raise the temperature of 1 kg of water by 1 degree Celsius is approximately 4,186 Joules. Therefore, to raise the temperature by 2 degrees Celsius, you would need about 8,372 Joules of energy.
You would need 20,920 Joules of heat to raise the temperature of 1kg of water by 5°C. This value is calculated using the specific heat capacity of water, which is 4186 J/kg°C.
It takes approximately 4186 joules to raise the temperature of one liter of water to its boiling point and an additional 2260 joules to convert it from liquid to vapor. So, in total, around 6446 joules are required to boil one liter of water at normal atmospheric pressure.
To raise the temperature of a substance, you need to calculate the heat energy using the specific heat capacity of the substance. Without knowing the specific heat capacity of the substance in question, it's not possible to determine the exact amount of energy required to raise the temperature from 30 to 45 degrees Celsius.
The specific heat capacity of water is 4.18 Joules/gram degrees Celsius. Therefore, it would take 4.18 Joules of energy to raise the temperature of 1 gram of water by 1 degree Celsius.
It takes 4186 joules to raise the temperature of 1 kilogram of water by 1 degree Celsius. The mass does make a difference.
The amount of energy required to raise the temperature of water by 1 degree Celsius is known as its specific heat capacity. For water, the specific heat capacity is 4.18 Joules/gram°C. This means that it takes 4.18 Joules of energy to raise the temperature of 1 gram of water by 1 degree Celsius.
specific heat is the amount of heat to be absorbed required to raise a substance 1 degree celsius. And by heat being absorbed, i mean energy, because specific heat is measured in joules
we use a match to raise the temperature of the alcohol that the wick absorbed
The answer is 53,683 kJ.
Specific heat capacity is the amount of energy required to raise the temperature of one unit mass of a substance by one degree Kelvin. Eg. The specific heat capacity of water is 4.18 joules per gram. So you need to transfer 4.18 joules of energy to one gram of water in order to raise it by one degree K Temperature on the other hand is the average kinetic energy of the particles in a substance.