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Heat energy Q = mass x specific heat capacity x temperature change.

Q = m*c*delta T

Q = Joules

m = kg

c (aluminum) = 895.8 J/kg

delta T = degr.C temp. change

Answer: Q = (20/1000) x 895.8 x 5 = 89.58 Joules

(Specific heat capacity of aluminum is obtained by multiplying its specific heat of 0.214 with c of water which is 4186 J/kg = 0.214 x 4186 = 895.8 J/kg).

Q: How many joules of energy are required to raise the temperature of 20g of aluminum from 10 degrees C to 15 degrees C?

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The energy required to raise the temperature 1 degree Celsius of 1 gram of water (1 mL) is 1 calorie (=4.18 J). So for 1 kg, 1Kcal (= 4180 J = 4.18 KJ) is required. To raise it 60 degrees, just multiply by 60 and for 10 kg multiply by 10 again. That would make 2.508 MJ (= 2508000 J) Now this is not completely accurate. The energy required to raise the temperature of water differs at 20 degrees from that at 60 degrees. The difference is small (~0.05 J or something like that) but still present.

200 BTU. I'm assuming your temperatures are in Fahrenheit, since all of your other measurements are in the Imperial system. A BTU is defined as the amount of energy required to raise the temperature of 1 pound water by 1 degree F, so the temperature is raised by 20 degrees, and 10 pounds of water: 20 x 10 = 200

The amount of energy that is required to 160 cfm of air from 10 to 170 degrees F is 200 btu. T he formula is weight x specific heat x temperature difference so we have10 pounds x 1.00 x 2010 for 10 pounds of water.

If you want to be pedantic, scientists measure temperature in kelvins, not degrees. Heat is energy and is measured in energy units, like joules.

You mean how much heat energy will be lost/transferred as you are losing Joules here. All in steam, so a simple q problem and no change of state. 2.67 kg = 2670 grams q = (2670 grams steam)(2.0 J/gC)(105 C - 282 C) = - 9.45 X 105 Joules ----------------------------------- This much heat energy must be lost to lower the temperature of the steam.

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The specific heat capacity of aluminum is 0.9 J/g°C. To calculate the energy required to raise the temperature of 0.2kg of aluminum by 3 degrees Celsius, you would use the formula: Energy = mass x specific heat capacity x temperature change. Substituting the values into the formula, Energy = 0.2kg x 0.9 J/g°C x 3°C = 0.54 Joules.

The specific heat capacity of aluminum is 900 J/kg°C. The change in temperature is 3°C. Using the formula Q = mcΔT, the energy required would be 0.2 kg * 900 J/kg°C * 3°C = 540 J. So, the energy required to raise the temperature is 540 Joules.

It would take more energy to increase the temperature of water by 5 degrees than aluminum. This is because water has a higher specific heat capacity, meaning it requires more energy to raise its temperature compared to aluminum.

The specific heat capacity of aluminum is 0.902 J/g°C. First, convert 3kg to grams (3000g). Then, calculate the change in temperature (23°C - 18°C = 5°C). Finally, use the formula Q = mcΔT to find the energy required: Q = 3000g * 0.902 J/g°C * 5°C.

The specific heat capacity of aluminum is 0.897 J/g°C. To calculate the energy required to heat 0.5kg of aluminum by a certain temperature change, you would use the formula: Energy = mass x specific heat capacity x temperature change If you have the temperature change, you can plug the values into the formula to find the total energy in joules.

If you are asking why a green heating system will not go above 68 degrees Fahrenheit then one reason is to save energy. The higher the temperature the more energy required to get to that temperature and the more energy required to keep that temperature.

The specific heat capacity of aluminum is 0.897 J/g°C. First we need to convert the mass to grams: 3 kg = 3000 g. Then we can use the formula: energy = mass x specific heat x change in temperature. Plugging in the values: energy = 3000 g x 0.897 J/g°C x (23°C - 18°C) = 13,485 J. So, 13,485 Joules of energy is required.

The heat energy required can be calculated using the formula: Q = mcΔT, where Q is the heat energy, m is the mass of the aluminum (0.055 kg), c is the specific heat capacity of aluminum (900 J/kg°C), and ΔT is the change in temperature (94.6°C - 22.4°C = 72.2°C). Plugging in the values, we get Q = 0.055 kg * 900 J/kg°C * 72.2°C = 3582.7 J. Hence, 3582.7 Joules of heat energy is needed to raise the temperature of the aluminum sample.

The energy required to raise the temperature of a substance can be calculated using the specific heat capacity formula: Q = mcΔT, where Q is the energy transferred, m is the mass of the substance, c is the specific heat capacity, and ΔT is the change in temperature. For aluminum, the specific heat capacity is 0.897 J/g°C. Converting the mass to grams (3000 g), the energy required would be: Q = 3000 g * 0.897 J/g°C * 5°C = 13,455 J.

The specific heat capacity of aluminum is 0.902 J/g°C. First we convert the mass from kg to grams (0.2 kg = 200 g). Then we calculate the energy using the formula: Q = mcΔT, where Q is the energy, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature. Plugging in the values, we get Q = 200g * 0.902 J/g°C * (18 - 15)°C. Solving this gives us the energy required to be approximately 541 J.

To raise the temperature of 1000 liters of water by 10 degrees Celsius, you would require approximately 239 kilowatt-hours of energy. This can be calculated using the specific heat capacity of water and the formula for calculating energy required for temperature change.

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