28
Good question. This is an 'analogue' of this puzzle: "Eight people meet for the first time. If they each shake hands with everyone else, how many handshakes are there?" There is a formula, but who would remember it?
Imagine you and I are both among the eight people. You would shake hands with seven others. I would say the same thing, and so could each of the others.
That gives 8x7 = 56, but you and I both counted the time we shook hands with one another , in fact each handshake is counted twice. The number of handshakes is actually 56/2 = 28.
This can be generalized to say that the number of ways to choose 2 objects from a group of n objects is n(n-1)/2.
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Two intersecting lines can always cover three non-collinear points.
Any three non-collinear points will define a single plane. A plane is composed of an infinite number of distinct lines.
Three
the lines which are not parallel to each other are non collinear lines
Through any two distinct points, exactly one line can be drawn. For 5 non-collinear points, each pair of points can form a line. The number of ways to choose 2 points from 5 is given by the combination formula ( \binom{5}{2} ), which equals 10. Therefore, 10 lines can be drawn through 5 non-collinear points.