If 32X + 53 = 501, then 32X = 448, and X = 448/32 = 14.
The answer is the expression 32x - 17.
32x + 8 – 34x
4x + 32x + 9 = 36x + 9
I read that as: (3) x (32x) x (3-2) - (32x) x (3) = 32x(3 x 3-2 - 3) = 32x (3-1 - 3) = 32x-1(1 - 32) = -8 x 32x-1 When multiplying the same base (number) to any power, keep the base and add the powers, eg: 32x x 3-1 = 32x + (-1) = 32x-1 3 x 3-2 = 31 x 3-2 = 31-2 = 3-1
32x-521 = -489
4y-32x = -28
Note that 16X is a factor of 32X [16X times 2 is 32X]. So now whether it's (32X)^4 or 32 times (X^4), that will still be the LCM, so the answer is 32X to the 4th power, just as it's stated in the question.
If 32X + 53 = 501, then 32X = 448, and X = 448/32 = 14.
48y - 32x
12x ^2 -32x-12
The answer is the expression 32x - 17.
32x + 8 – 34x
4x + 32x + 9 = 36x + 9
I read that as: (3) x (32x) x (3-2) - (32x) x (3) = 32x(3 x 3-2 - 3) = 32x (3-1 - 3) = 32x-1(1 - 32) = -8 x 32x-1 When multiplying the same base (number) to any power, keep the base and add the powers, eg: 32x x 3-1 = 32x + (-1) = 32x-1 3 x 3-2 = 31 x 3-2 = 31-2 = 3-1
y2 = 32x y = ±√32x the vertex is (0, 0) and the axis of symmetry is x-axis or y = 0
Either: (7x + 4)(x + 4) = 7x2 + 32x + 16 or: (7x - 4)(x - 4) = 7x2 - 32x + 16