1 Pa = 1 N/m2 = 10−5 bar = 10.197×10−6 at = 9.8692×10−6 atm,
270
Water column head is expressed either as the height of the column ... 6 meters here ... or else as the pressure at the bottom ... 58.842 kPa here. 'Kg' can't be a unit of water column head, and the diameter of the column is irrelevant.
14250 litres
10 meters of water depth equals about 1 atmosphere.
The diameter of the water column does not affect the pressure.It is the height of the column that determines the pressure at the base.(and also the barometric pressure and temperature).
The height of a water column that extends above the point of measurement affects the water pressure at that point. This height, also known as head, is commonly measured in feet or meters and represents the potential energy available to create pressure. The higher the head, the greater the water pressure.
The maximum height to which water can be drunk through a straw is about 10 meters (33 feet), due to the limitations of atmospheric pressure. Beyond this height, the pressure differential required to lift the water against gravity would exceed the capacity of a person's lungs to create suction.
approximately 0.8 bar
c-34.3kpa
The pressure at any point at the bottom of the tank is determined by the height of the water column above that point. The pressure is given by the formula P = ρgh, where ρ is the density of water (around 1000 kg/m^3), g is the acceleration due to gravity (around 9.81 m/s^2), and h is the height of the water column (3.5 meters in this case). Plugging in these values will give you the pressure at the bottom of the tank.
The pressure at the bottom of the tank is determined by the weight of the water above that point. To calculate the pressure, you would use the formula P = ρgh, where P is pressure, ρ is density, g is acceleration due to gravity, and h is the height of the water column. Given the height is 4 meters and water density is 1000 kg/m^3, you can calculate the pressure.
12.6 meters 0.1 bar is gained for every meter.
The pressure is ONLY dependent on the height of the water column, not on its exact shape (for instance, whether it is narrower or wider towards the top). The water pressure is approximately 1 atmosphere (or 1 bar) for every 10 meters. For other liquids, use appropriate conversion factors, depending on the density of the liquid.
THe ideal amount is 50% air pressure and 50% water. SHoot from 4-6 bar. I got mine to 92 meters
The hydrostatic pressure, which is counted with (density*gravitational acceleration*height) is about 1000kg/m3*9.8m/s2*90m = 882 000Pa now you add the pressure ontop of the water, which normally is the atmospheric pressure (~100000Pa) and you get 982000Pa.Also, do your own homework :3
water is 1/13.5 as dense as mercury.Therefore, since mercury maintains a height of 760 mm at sea level:760/13.5 = 10,260 mm, or 10.26 meters
In theory, the answer is approx 10.33 metres but that assumes that you could create (and maintain) such pressure ... very unlikely!