how many mg in 20 meg potassium
ANSWER: 1500 mg.
1 cL = 10 mL so 93 cL = 93*10 = 930 mL. Simple!
0.1 cl = 1 ml.
4560 ml. Algebraic Steps / Dimensional Analysis456 cl*10 ml 1 cl=4,560 ml
how many mg in 20 meg potassium
ANSWER: 1500 mg.
i believe 10 meqs of potassium is equal to 390 mg's of potassium, therefore, one meq, is equal to 39 mg's potassiumNot sure where you get your answer but according to drugs.com 10meg is equal to 750 mg of potassium20mEq of potassium chloride is 781.960 mg of elemental potassium [K], and 709.060 mg of elemental chlorine [Cl] (which is 1491.0 mg of potassium chloride [KCl]). Here's how to figure it:_________________mg = (mEq • atomic, molecular or formula weight) / valenceAtomic weight of potassium [K] is 39.0983Atomic weight of chlorine [Cl] is 35.453The molecular weight of potassium chloride [KCl] is sum of the atomic weights above: 74.551 (rounded)The valence of potassium chloride is 1Thus:(20mEq potassium chloride • 74.551) / 1 = 1491.0 mg potassium chlorideWhich breaks down to 781.960 mg of elemental potassium [K], and 709.060 mg of elemental chlorine [Cl]._________________
1 milliequivalent (meq) of KCl is equal to 1 millimole (mmol) of KCl since the valence of potassium (K) and chloride (Cl) is 1.
i believe 10 meqs of potassium is equal to 390 mg's of potassium, therefore, one meq, is equal to 39 mg's potassiumNot sure where you get your answer but according to drugs.com 10meg is equal to 750 mg of potassium20mEq of potassium chloride is 781.960 mg of elemental potassium [K], and 709.060 mg of elemental chlorine [Cl] (which is 1491.0 mg of potassium chloride [KCl]). Here's how to figure it:_________________mg = (mEq • atomic, molecular or formula weight) / valenceAtomic weight of potassium [K] is 39.0983Atomic weight of chlorine [Cl] is 35.453The molecular weight of potassium chloride [KCl] is sum of the atomic weights above: 74.551 (rounded)The valence of potassium chloride is 1Thus:(20mEq potassium chloride • 74.551) / 1 = 1491.0 mg potassium chlorideWhich breaks down to 781.960 mg of elemental potassium [K], and 709.060 mg of elemental chlorine [Cl]._________________
Chloride Normal Range= Chloride 95-105 mEq/L
In KCl, there are two elements: potassium (K) and chlorine (Cl).
Potassium (K) and Chlorine (Cl) are the elements present in potassium chloride (KCl).
1 cl = 10 ml ⇒ 408 cl = 408 x 10 ml = 4080 ml
53 dL = 530 cL 53 x 10 = 530 10 cL = 1 dL
1 cL = 10 mL so 93 cL = 93*10 = 930 mL. Simple!
There are 10 cL in a dL.