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To find the volume of the 0.500 M KCl solution needed to prepare 100.0 mL of 0.100 M KCl, you can use the dilution equation (C_1V_1 = C_2V_2). Here, (C_1 = 0.500 , \text{M}), (C_2 = 0.100 , \text{M}), and (V_2 = 100.0 , \text{mL}). Rearranging the equation to solve for (V_1) gives:

[ V_1 = \frac{C_2V_2}{C_1} = \frac{0.100 , \text{M} \times 100.0 , \text{mL}}{0.500 , \text{M}} = 20.0 , \text{mL}. ]

Thus, you would need 20.0 mL of the 0.500 M KCl solution.

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2mo ago

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