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How many milliliters of a 50 percent acid solution and how many milliliters of a 20 percent acid solution must be mixed to produce 36 mL of a 30 percent acid solution?
A
nswer:12mL of 50% solution and 24mL of 20% solution must be mixed to produce 36mL of a 30% acid solution
Let x = 50% acid solution
y = 20% acid solutionEquations:
x + y = 36mL ----equation (1)
0.5x + 0.2y = 0.3 * 36
0.5x + 0.2y = 10.8
multiplying by 10
5x + 2y = 108 ----equation (2)
eliminating equations (1) and (2)
-2(x + y = 36)-2
-2x -2y = -72
5x +2y = 108
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3x = 36
x=12
substitute x=12 to equation (1)
12 + y = 36
y = 36 - 12
y = 24
thus 12mL of 50% solution and 24mL of 20% solution must be mixed to produce 36mL of a 30% acid solution
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