0
Oh honey, let me break it down for you. Avogadro's number tells us that 1 mole is equal to 6.022 x 10^23 atoms. So, to find out how many moles are in 1.25 x 10^25 atoms of phosphorus, you just need to divide the number of atoms by Avogadro's number. That gives you approximately 20.75 moles of phosphorus.
What else can I help you with?
How many B atoms are there in 2.47 moles of B?
The conversion factor between atoms and moles is Avogadro's number: 6.02 x 1023 "things" / moleTo convert moles to atoms:atoms B = 2.47 mol B6.02 x 1023 atoms B = 1.49E+24 atoms B1 mol BMultiply by atoms per mole. Moles cancel out.
How many k atoms are in 78.2 grams of k?
To find the number of potassium (K) atoms in 78.2 grams, first determine the molar mass of potassium, which is approximately 39.1 g/mol. Dividing 78.2 grams by the molar mass gives about 2.00 moles of potassium. Since one mole contains approximately (6.022 \times 10^{23}) atoms (Avogadro's number), multiplying 2.00 moles by (6.022 \times 10^{23}) results in approximately (1.20 \times 10^{24}) potassium atoms.
How many moles of rice grains are equyal to 1.807x1023 grains of rice?
To find the number of moles of rice grains equivalent to 1.807 x 10^23 grains, you can use Avogadro's number, which is approximately 6.022 x 10^23 grains per mole. By dividing the number of rice grains by Avogadro's number, you get: ( \text{Moles} = \frac{1.807 \times 10^{23}}{6.022 \times 10^{23}} \approx 0.300 ) moles. Thus, 1.807 x 10^23 grains of rice is approximately 0.300 moles.
How many copper atoms are in a pure copper statue with a mass of 129 kg?
The atomic weight of copper is 63.546 grams per mole. 129 kg is equal to 129000 grams. So there are 2030.03 moles of copper. There are 6.022 x 10^23 copper atoms in a mole. So there are 12.22 x 10^26 atoms.
How many grams are there in 4.5 x 1022 molecules of ba(no2)2?
To find the mass in grams of 4.5 x 10²² molecules of barium nitrate, Ba(NO₂)₂, first determine the molar mass of Ba(NO₂)₂. The molar mass is approximately 199.34 g/mol. Next, convert the number of molecules to moles using Avogadro's number (6.022 x 10²³ molecules/mol): [ \text{moles} = \frac{4.5 \times 10^{22}}{6.022 \times 10^{23}} \approx 0.0747 \text{ moles}. ] Finally, multiply the number of moles by the molar mass to find the mass: [ \text{mass} = 0.0747 \text{ moles} \times 199.34 \text{ g/mol} \approx 14.89 \text{ grams}. ]
How many moles of Mg is 2.01 times 10x22 atoms?
2.01x10^22 atoms x 1 mole/6.02x10^23 atoms = 0.0334 moles
How many atoms are in 4 moles of lithium?
To find the number of atoms in 4 moles of lithium, you can use Avogadro's number, which is approximately (6.022 \times 10^{23}) atoms per mole. Therefore, in 4 moles of lithium, the number of atoms is (4 \times 6.022 \times 10^{23} = 2.409 \times 10^{24}) atoms.
How many moles are in 1.63x10 to the 24th atoms?
To find the number of moles in (1.63 \times 10^{24}) atoms, you can use Avogadro's number, which is approximately (6.022 \times 10^{23}) atoms per mole. Divide the number of atoms by Avogadro's number: [ \text{moles} = \frac{1.63 \times 10^{24}}{6.022 \times 10^{23}} \approx 2.71 \text{ moles}. ] Thus, there are approximately 2.71 moles in (1.63 \times 10^{24}) atoms.
How many moles of nitrogen are contained in 1.61 x 10 atoms of nitrogen?
To find the number of moles of nitrogen in (1.61 \times 10^{24}) atoms, you can use Avogadro's number, which is approximately (6.022 \times 10^{23}) atoms per mole. Calculating the moles: [ \text{Moles of nitrogen} = \frac{1.61 \times 10^{24} \text{ atoms}}{6.022 \times 10^{23} \text{ atoms/mole}} \approx 2.68 \text{ moles} ] Thus, there are approximately 2.68 moles of nitrogen in (1.61 \times 10^{24}) atoms.
How many moles is 2.80 times 10 to the twenty third power atoms of silicon?
The answer is 0,465 moles.
How many moles of nickel atoms are there in 8.00 x 109 Ni atoms?
To find the number of moles of nickel atoms in (8.00 \times 10^9) Ni atoms, you can use Avogadro's number, which is approximately (6.022 \times 10^{23}) atoms/mole. The calculation is as follows: [ \text{Moles of Ni} = \frac{8.00 \times 10^9 \text{ atoms}}{6.022 \times 10^{23} \text{ atoms/mole}} \approx 1.33 \times 10^{-14} \text{ moles} ] Thus, there are approximately (1.33 \times 10^{-14}) moles of nickel atoms in (8.00 \times 10^9) Ni atoms.
How many atoms of magnesium in 2.5 moles of magnesium?
To find the number of atoms in 2.5 moles of magnesium, you can use Avogadro's number, which is approximately (6.022 \times 10^{23}) atoms per mole. Multiplying 2.5 moles by Avogadro's number gives you: [ 2.5 , \text{moles} \times 6.022 \times 10^{23} , \text{atoms/mole} \approx 1.51 \times 10^{24} , \text{atoms}. ] Therefore, there are about (1.51 \times 10^{24}) atoms of magnesium in 2.5 moles.
How many atoms are in 6.2 moles of Al?
To find the number of atoms in 6.2 moles of aluminum (Al), you can use Avogadro's number, which is approximately (6.022 \times 10^{23}) atoms per mole. Therefore, the calculation is (6.2 , \text{moles} \times 6.022 \times 10^{23} , \text{atoms/mole} \approx 3.74 \times 10^{24} , \text{atoms}). Thus, there are approximately (3.74 \times 10^{24}) atoms in 6.2 moles of Al.
How many moles of phosphorus are in 392 grams of phosphorus?
Quite a few! 392 grams phosphorous (1 mole P/30.97 grams) = 12.7 moles phosphorous ===================
How many C atoms are in 2.4 moles of CO2?
In 2.4 moles of CO2, there are 2.4 moles of carbon (C) atoms because each molecule of CO2 contains one carbon atom. To find the number of carbon atoms, you can multiply the number of moles by Avogadro's number (approximately (6.022 \times 10^{23}) atoms/mole). Therefore, the total number of carbon atoms is (2.4 \text{ moles} \times 6.022 \times 10^{23} \text{ atoms/mole} \approx 1.44 \times 10^{24} \text{ C atoms}).
How many atoms are there in 7.52 moles of Phosphorus?
There are 4.54 x 10^24 atoms in 7.52 moles of Phosphorus because 1 mole of Phosphorus contains 6.022 x 10^23 atoms. Multiplying this by the number of moles gives the total number of atoms in 7.52 moles.
How many atoms are in in 1.004 moles of bismuth?
There are (6.023 \times 10^{23}) atoms in 1 mole of any substance (Avogadro's number). Therefore, there are (1.004 \times 6.023 \times 10^{23} \approx 6.05 \times 10^{23}) atoms in 1.004 moles of bismuth.
