the integral of ln(sin(x)) is: -x*ln|1 - e2ix| + x*ln|sin(x)| + (i/2)*(x2 + Li2(e2ix)) + C where Li2 is the second order ploylogarithmic function.
Better call it Li2(x).
Get Hertz with this formula. Z = 3 for Li.Hertz = (3.29 X 1015 s -1)*Z2*(1/Nf2 - 1/Ni2)We will reverse initial and final to avoid negatives.Hertz = (3.29 X 1015 s -1)(32)(1/12 - 1/42)Hertz = (9.87 X 1015)(15/16)= 9.25 X 1015 Hertz------------------------------Now, this formula.Wavelength = speed of light/HertzWavelength = 2.998 X 108 m/s/9.25 X 1015 Hertz= 3.24 X 10 -8 meters (109/1 meter)= 32.4 nanometers==============
Yes, Li2 is paramagnetic because it has two unpaired electrons, making it attracted to a magnetic field.
The Bohr model applies to atoms or ions with a single electron, such as hydrogen or singly ionized ions like He+. For Be (beryllium), which has 4 electrons, the Bohr model would not apply accurately due to multiple electrons influencing each other's behavior. For K (potassium), Li2+ (lithium with a +2 charge), and other multi-electron ions, the Bohr model would also not be appropriate due to their more complex electronic structures.
No, Li2- does not exist in the gas phase. The lithium ions in Li2- would typically form bonds with other atoms to create stable compounds in the gas phase.
The chemical formula of dilithium carbonate is Li2CO3.
This cannot be answered. This does not make sense.
Yes
It is unlikely for li2- to exist in the gas phase as lithium typically forms cations, not anions. Additionally, the stability of Li2- in the gas phase would be hindered by the repulsive forces between the two negatively charged lithium ions.
Lithium is a cation because it has a positive charge. It loses one electron to achieve stability and form the Li+ ion.
Yes, N2 and O2 have unpaired electrons because they have a triple bond between the nitrogen or oxygen atoms, resulting in one unpaired electron in each molecule. Li2 does not have unpaired electrons because it forms a stable bond with shared electrons within the lithium atoms.
O2,N2,H2,F2,Cl2,Li2,Na2
The chemical formula of Li2CrO4 is lithium chromate.
The oxidation number of Li in Li2 is +1. Each Li atom has an oxidation number of +1 in ionic compounds.