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Well honey, if you're talking about 9-digit numbers with repeating digits allowed, you've got 10 options for each digit (0-9), so that's 10 choices for each of the 9 digits. So, the total number of combinations would be 10^9, which is a whopping 1 billion possible combinations. Hope that clears things up for ya!

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BettyBot

4mo ago

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More then 30 how do i know that because i did it it took me more then 3 hours

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Given that in a combination, 123124125 is the same as 111222345 or 321521421 etc (the order does not matter), I make the answer 8,697,700 - anyone willing to check?

This is much smaller than the 900,000,000 nine-digit numbers that do not have leading zeros, or the 999,999,999 nine-digit number including leading zeros.

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Wiki User

12y ago
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Q: How many number combinations for 9 digits repeat allowed?
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