The equation is |x|2-3|x|+2=0
If x>0
then the equation becomes
x2-3x+2=0
(x-2)(x-1)=0
x=1,2
We get two values for x.
If x<0, then the equation is again
x2-3x+2=0
We again get two values.
Therefore, the total number of solutions=4.
The discriminant must be a perfect square or a square of a rational number.
When there is a negative number under the square root in a quadratic equation, it indicates that the equation has no real solutions. Instead, it results in complex or imaginary solutions, as the square root of a negative number involves the imaginary unit (i). This situation occurs when the discriminant (the part under the square root in the quadratic formula) is negative. Consequently, the quadratic graph does not intersect the x-axis, indicating no real roots.
To solve a square root equation, first isolate the square root term on one side of the equation. Then, square both sides to eliminate the square root. After squaring, solve the resulting equation for the variable. Finally, check your solutions to ensure they are valid, as squaring can introduce extraneous solutions.
Technically,no. A radical equation has a radical (Square root) in it, and has two solutions because the square root can be positive or negative.
This is a quadratic equation which will have two solutions: X2 = 4x+5 Rearrange the equation: x2-4x-5 = 0 Factor the equation: (x+1)(x-5) = 0 So the solutions are: x = -1 or x = 5
The discriminant must be a perfect square or a square of a rational number.
A positive number has two square roots, that is, there are two solutions to an equation like x2 = 100. The "principal square root" refers to the positive solution.
When there is a negative number under the square root in a quadratic equation, it indicates that the equation has no real solutions. Instead, it results in complex or imaginary solutions, as the square root of a negative number involves the imaginary unit (i). This situation occurs when the discriminant (the part under the square root in the quadratic formula) is negative. Consequently, the quadratic graph does not intersect the x-axis, indicating no real roots.
To solve a square root equation, first isolate the square root term on one side of the equation. Then, square both sides to eliminate the square root. After squaring, solve the resulting equation for the variable. Finally, check your solutions to ensure they are valid, as squaring can introduce extraneous solutions.
on these problems you have o say it out to figure it out three times 3times something the square of a number x so the answer is 3x2
Technically,no. A radical equation has a radical (Square root) in it, and has two solutions because the square root can be positive or negative.
This is a quadratic equation which will have two solutions: X2 = 4x+5 Rearrange the equation: x2-4x-5 = 0 Factor the equation: (x+1)(x-5) = 0 So the solutions are: x = -1 or x = 5
An equation can be determine to have no solution or infinitely many solutions by using the square rule.
The two solutions are coincident.
Yes. Quite often, if you don't, you'll lose solutions. That is, the transformed equation - after taking square roots - will have less solutions than the original equation.
There are no real solutions to this equation because you cannot take the square root of a negative number. However,x2 + 4 = 0x2 = -4sqrt(x2) = sqrt(-4)x = 2i, -2ihere are the imaginary solutions.
Two cases in which this can typically happen (there are others as well) are: 1. The equation includes a square. Example: x2 = 25; the solutions are 5 and -5. 2. The equation includes an absolute value. Example: |x| = 10; the solutions are 10 and -10.