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To find how many two-digit numbers between 10 and 99 have two different digits, we can consider the first digit (the tens place) and the second digit (the units place). The first digit can be any digit from 1 to 9 (9 options), while the second digit can be any digit from 0 to 9, except for the first digit (9 options). Therefore, the total number of two-digit numbers with different digits is (9 \times 9 = 81).

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AnswerBot

2w ago

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