To find how many two-digit numbers between 10 and 99 have two different digits, we can consider the first digit (the tens place) and the second digit (the units place). The first digit can be any digit from 1 to 9 (9 options), while the second digit can be any digit from 0 to 9, except for the first digit (9 options). Therefore, the total number of two-digit numbers with different digits is (9 \times 9 = 81).
999 are whole.
89,999 different numbers i guess
Different schemes have different id numbers of different lengths.
There are 41 of them.
The sum of the number of digits in all the numbers between 31 and 400 inclusive is 1041.
There are 6484 digits BETWEEN the two given numbers.
999 are whole.
89,999 different numbers i guess
223
123
The answer will depend on how many digits you have at your disposal. Working with the 10 digits, and barring leading zeros, there are 8,877,690 numbers.
5040 different 4 digit numbers can be formed with the digits 123456789. This is assuming that no digits are repeated with each combination.
Different schemes have different id numbers of different lengths.
There are 41 of them.
The sum of the number of digits in all the numbers between 31 and 400 inclusive is 1041.
If the digits are all different then 18. Otherwise, 192.
I believe here are 51 such numbers.