Every third number in a series of numbers is divisible by 3 (i.e. 1,2,3,4,5,6,7,8,9... and so on).
Therefore, the number of numbers divisible by 3 from 1 to any number is the last multiple of 3 which is smaller than that number, divided by 3. This can be realized by doing some simple algebra:
1x3=3, 2x3=6, 3x3=9, ..., Nx3=174 -> N=174/3=58
Note that 174 is the last multiple of 3 before reaching 175.
Trick question all numbers are divisible by four ,but only 175 result in whole numbered answers
35/41. Divide by common numbers until they have no numbers in common that they are divisible by. I divided by 5.
There are 175 such numbers.
29.1667
Yes, the result is 175.
Trick question all numbers are divisible by four ,but only 175 result in whole numbered answers
2275 is the smallest number that is divisible by both 175 and 325. All multiples of 2275 are divisible by both these numbers. Ex: 2275 4550 6825 9100 and so on...
1, 5, 7, 25, 35, 125, 175, 875
There are many. One example is -sqrt(175) < -3 < -2 < +sqrt(175)
35/41. Divide by common numbers until they have no numbers in common that they are divisible by. I divided by 5.
There are 175 such numbers.
29.1667
Yes, the result is 175.
Yes, the result is 175.
1. They are coprime.
The number 350 is even, so it's divisible by 2; 350/2 = 175. 175 ends with a 5, so it's divisible by 5; 175/5 = 35. The same applies to 35; 35/5 = 7. Our factors are now 2 X 5 X 5 X 7, which are all prime numbers. Therefore, that's the prime factorization of 350: 2 X 52 X 7.
Well, 175/365 are both divisible by 5 so 35/73.