0
Anonymous
Three: 1 7 49.
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Six: 1 2 7 14 49 98.
The HCF of both numbers is 1
4 and 8
Infinitely many.
nCr = n!/((n-r)!r!) → 49C8 = 49!/((49-8)!8!) = 49!/(41!8!) = 450,978,066 combinations.