There are 278 5-digit numbers less than 20,000 that are divisible by both four and nine.
14. Assuming dealing with only counting numbers (ie integers greater than 0): Numbers divisible by 5 or 7 are their multiples. 50 ÷ 5 = 10 → last multiple of 5 less than 50 is 9 x 5 → 9 numbers less than 50 are divisible by 5 50 ÷ 7 = 71/7 → last multiple of 7 less than 50 is 7 x 7 → 7 numbers less than 50 are divisible by 7 Numbers divisible by both are those which are multiples of their lowest common multiple = 35 50 ÷ 35 = 115/35 → last multiple of 35 less than 50 is 1 x 35 → 1 number less than 50 is divisible by both 5 and 7 and needs to be removed from both the above counts. → (9 - 1) + (7 - 1) = 14 numbers less than 50 are divisible by 5 or 7 but not both. If there is no restriction on numbers being greater than 0, there are infinitely many numbers as it includes the infinite number of negative numbers which are all less than 50 and provide an infinite number of numbers divisible by 5 or 7 but not both.
75,000,000,000 of them.
Numbers up to 200 divisible by both 2 and 3 = numbers to 200 divisible by 2*3 = 6 which is int(200/6) = int(33.33) = 33
19
4,8,12,16,20,24,28,32,36,40,44,48,52,56,60,64,68,72,76,80,84,88,92,96,100 ............ on and on and on to infinity and beyond LOL !!!!!!!!!
14 of them.
The numbers that are divisible by both 3 and 5 have to be a factor of 15. That leaves 15, 30, 45, 60, 75, and 90. There are 6 numbers less than 100 divisible by 3 and 5
12
There are 278 5-digit numbers less than 20,000 that are divisible by both four and nine.
14. Assuming dealing with only counting numbers (ie integers greater than 0): Numbers divisible by 5 or 7 are their multiples. 50 ÷ 5 = 10 → last multiple of 5 less than 50 is 9 x 5 → 9 numbers less than 50 are divisible by 5 50 ÷ 7 = 71/7 → last multiple of 7 less than 50 is 7 x 7 → 7 numbers less than 50 are divisible by 7 Numbers divisible by both are those which are multiples of their lowest common multiple = 35 50 ÷ 35 = 115/35 → last multiple of 35 less than 50 is 1 x 35 → 1 number less than 50 is divisible by both 5 and 7 and needs to be removed from both the above counts. → (9 - 1) + (7 - 1) = 14 numbers less than 50 are divisible by 5 or 7 but not both. If there is no restriction on numbers being greater than 0, there are infinitely many numbers as it includes the infinite number of negative numbers which are all less than 50 and provide an infinite number of numbers divisible by 5 or 7 but not both.
The lists of numbers divisible by and not divisible by 600 are both infinite.
Four. 24, 48, 72, and 96
between 1 and 600 inclusive there are:300 numbers divisible by 2200 numbers divisible by 3100 numbers divisible by both 2 and 3400 numbers divisible by 2 or 3.
According to a source, there are 44 counting numbers less than 200 that are exactly divisible by either 6 or 9, or by both. To determine the total count, we can follow these steps: Find out how many counting numbers less than 200 are divisible by 6. The last number under 200 that is divisible by 6 is 198, and since 198 is the 33rd multiple of 6, there are 33 such numbers. Next, figure out how many numbers are divisible by 9. The last number under 200 that is divisible by 9 is also 198, and since 198 is the 22nd multiple of 9, there are 22 such numbers. Some numbers will be divisible by both 6 and 9, but we need to avoid counting these twice. So, determine which numbers are divisible by both (these are actually multiples of 18). The last number under 200 that is divisible by 18 is also 198, and since it is the 11th multiple of 18, there are 11 such numbers. Finally, add the two individual counts from steps 1 and 2 together and subtract the count from step 3 to eliminate double counting: 33 + 22 - 11 = 44. Therefore, there are 44 different counting numbers less than 200 that are exactly divisible by either 6 or 9 or both.
75,000,000,000 of them.
17 odd numbers.