Well, honey, let me break it down for you. The prime factorization of 432 is 2^4 * 3^3. To find the number of perfect square factors, you look at the exponents of the prime factors. Since perfect squares have even exponents, you can choose 2 exponents for 2 (0, 2, or 4) and 2 exponents for 3 (0 or 2). So, you have 3 choices for 2 and 2 choices for 3, giving you a total of 3 * 2 = 6 perfect square factors of 432.
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The positive integer factors of 36 are: 1, 2, 3, 4, 6, 8, 9, 12, 18, 36 The perfect squares in this list are: 1, 4, 9, 36
factors are 2 x 36, 4 x 18 and 8 x 9 so there are three perfect squares, 4, 9 and 36.
In terms of prime factors, 1008 = 24*32*7 Then since 24 and 32 are perfect squares, all that is required is to make 7q a perfect square and so q = 7.
perfect squares
The proposition in the question is simply not true so there can be no answer!For example, if given the integer 6:there are no two perfect squares whose sum is 6,there are no two perfect squares whose difference is 6,there are no two perfect squares whose product is 6,there are no two perfect squares whose quotient is 6.