In a square, there are four pairs of sides that are perpendicular to each other. Each side of the square forms a right angle (90 degrees) with its adjacent sides. Therefore, the four pairs of perpendicular sides are: (top, left), (top, right), (bottom, left), and (bottom, right). Additionally, the diagonals of the square are also perpendicular to each other, adding one more pair, resulting in a total of five pairs of perpendicular lines.
There are 2 pairs and together they make 4 right angles in a square which also has a pair of perpendicular diagonals that intersect at right angles
It has 2 pairs.
4 pairs
none
two.
Yes a square has 2 pairs of perpendicular sides actually, 4!
Perpendicular would be at a right angle. If your sides are abcd, then ab, bc, cd, and da are perpendicular pairs.
8
A square has four perpendicular sides.
Each lateral face is perpendicular to its lateral neighbours so that makes 4 pairs. In addition, opposite lateral faces may be perpendicular, making 6 pairs in all.
There are 2 pairs and together they make 4 right angles in a square which also has a pair of perpendicular diagonals that intersect at right angles
How many pairs of perpendicular sides does this figure have?
It has 2 pairs.
4 pairs
Can have no pairs or one pair...
A square and a rhombus
none