40. Excluding numbers starting with 0.
There are lots of them: one such is 2304.
To find the two-digit counting numbers less than 30, we consider the numbers from 10 to 29, which gives us 20 two-digit numbers. The multiples of 20 that are two-digit numbers are 20. Since 20 is already included in the count of two-digit numbers less than 30, the total remains 20. Therefore, there are 20 two-digit counting numbers that are either less than 30 or a multiple of 20.
-200
Not sure what you're asking, but here are some examples of numbers that have a tens digit less than the ones digit: 13, 205, 1367, 29.632
While I'm tempted to tell you to do your own homework, this is intriguing enough that I'm willing to spend some time helping you to work it out.First: by four digit palindromes that means numbers of the form ABBA.A is constrained by "less than 5000". A can only be 0, 1, 2, 3, or 4, because otherwise ABBA would be greater than 5000 (the lowest possible ABBA number where A is 5 or greater is 5005 ... which is over 5000).A is further constrained by "4 digit". It can't be 0, because by convention we don't write leading zeroes and then ABBA would only be a three digit number.So A can be 1, 2, 3, or 4 (4 distinct possibilities).There are no constraints on B. It can be any digit (including 0), which means there are 10 distinct possibilities.Since once we specify both A and B we're done, that means there are (4 possibilities for A) x (10 possibilities for B) = 40 four-digit palindromes less than 5000.
What is the greatest palindromic number less than 999?
It is 77.It is 77.It is 77.It is 77.
There are lots of them: one such is 2304.
To find the two-digit counting numbers less than 30, we consider the numbers from 10 to 29, which gives us 20 two-digit numbers. The multiples of 20 that are two-digit numbers are 20. Since 20 is already included in the count of two-digit numbers less than 30, the total remains 20. Therefore, there are 20 two-digit counting numbers that are either less than 30 or a multiple of 20.
-200
anywhere from 4001-4999
Not sure what you're asking, but here are some examples of numbers that have a tens digit less than the ones digit: 13, 205, 1367, 29.632
While I'm tempted to tell you to do your own homework, this is intriguing enough that I'm willing to spend some time helping you to work it out.First: by four digit palindromes that means numbers of the form ABBA.A is constrained by "less than 5000". A can only be 0, 1, 2, 3, or 4, because otherwise ABBA would be greater than 5000 (the lowest possible ABBA number where A is 5 or greater is 5005 ... which is over 5000).A is further constrained by "4 digit". It can't be 0, because by convention we don't write leading zeroes and then ABBA would only be a three digit number.So A can be 1, 2, 3, or 4 (4 distinct possibilities).There are no constraints on B. It can be any digit (including 0), which means there are 10 distinct possibilities.Since once we specify both A and B we're done, that means there are (4 possibilities for A) x (10 possibilities for B) = 40 four-digit palindromes less than 5000.
18 numbers are there
40, 51, 62, 73, 84, and 95
The ones digit in the product from multiplying the 305 prime numbers less than 2012 is 0 because the ones digit becomes 0 after 2 and 5 have been multiplied and remains unchanged after more prime numbers are multiplied.
30