Wiki User
β 14y agoTen. They are all of the form 1xx1 where x can take the values 0,1,2,...,9
Wiki User
β 14y agoDo a search on Google, for "prime numbers" table, or "prime numbers" list, and you will surely find something.I cannot tell precisely without looking up a table or doing some longish calculus but as a gross estimatation there should be about this many prime numbers between 1000 and 2000:2000 / ln(2000) - 1000 / ln(1000) =~ 263 - 144 = 119Actual number of primes between 1000 and 2000 should be a little above 119(in the range [140, 160] i think)
1000
2000.The smallest four-digit number there can be is 1000. So, add 1000 and 1000 to get 2000, then least sum you can get when adding two four-digit numbers.
Three numbers.
64 is one possible answer.
All numbers between 1000 and 2000, or anywhere else, can be expressed as a power of another number.
300
Do a search on Google, for "prime numbers" table, or "prime numbers" list, and you will surely find something.I cannot tell precisely without looking up a table or doing some longish calculus but as a gross estimatation there should be about this many prime numbers between 1000 and 2000:2000 / ln(2000) - 1000 / ln(1000) =~ 263 - 144 = 119Actual number of primes between 1000 and 2000 should be a little above 119(in the range [140, 160] i think)
3000
They are 1024, 1125 and 1372.
1000 to 2999 inclusive so 2000 numbers.
1000+1000 1000x2
The two thousand numbers either side of 1999 are 1000 and 2000. The difference between 1999 and these numbers are 999 and 1 respectively. Clearly the second is nearer.
1000
999 (whole) numbers. THere are the same number whether they are counted in ascending, descending or other order.
3000 It is 2000 more than 1000 and 2000 less than 5000 To find a halfway point (which is also the average), add the numbers together and divide by 2.
M-MM