It is: x = k whereas k is a numerical value on the x axis and is a line parallel to the y axis through (k, 0)
The letter K contains two right angles. A right angle is defined as an angle that measures exactly 90 degrees. In the letter K, there are two perpendicular lines meeting at a corner, each forming a right angle.
The given question seems to be muddle up but parallel lines have the same slope but with different y intercepts
In order for the two equations kx-8y-32 equals 0 and 4x-5y +17 equals 0 to produce parallel lines, "k" in the first equaation needs to equal 2. Then, when you plot the lines on a graph they lie parallel, with one equation liying above the y axis, and the other below it.
The question is curiously vague. Do the two lines exist in the same plane? If they do, then they must intersect somewhere -- unless they are parallel. For non-parallel lines, the distance between the two lines at the point of intersection is zero. For parallel lines, the shortest distance between them is the length of the line segment that is perpendicular to both. For intersecting lines, there is an infinite number of distances between the infinite number of pairs of points on the lines. But for any pair of points -- one point on line A and another on line B -- the shortest distance between them will still be a straight line. Given two lines in 3D (space) there are four possibilities # the lines are collinear (they overlap) # the lines intersect at one point # the lines are parallel # the lines are skew (not parallel and not intersecting) The question of "shortest distance" is only interesting in the skew case. Let's say p0 and p1 are points on the lines L0 and L1, respectively. Also d0 and d1 are the direction vectors of L0 and L1, respectively. The shortest distance is (p0 - p1) * , in which * is dot product, and is the normalized cross product. The point on L0 that is nearest to L1 is p0 + d0(((p1 - p0) * k) / (d0 * k)), in which k is d1 x d0 x d1.
No
The lower case k, as shown in the question, has 0 lines of symmetry.
one
If both lines are parallel then they will have the same slope but with different y intercepts
It is: x = k whereas k is a numerical value on the x axis and is a line parallel to the y axis through (k, 0)
The letter K contains two right angles. A right angle is defined as an angle that measures exactly 90 degrees. In the letter K, there are two perpendicular lines meeting at a corner, each forming a right angle.
lowercase k doesn't have any.uppercase K has one, horizontally.
The given question seems to be muddle up but parallel lines have the same slope but with different y intercepts
In the upper case Roman alphabet, and depending on the font being used: A,B,D,G,K,P,Q,V,W,X and Y. In some case the sloped lines of K may be perpendicular.
In order for the two equations kx-8y-32 equals 0 and 4x-5y +17 equals 0 to produce parallel lines, "k" in the first equaation needs to equal 2. Then, when you plot the lines on a graph they lie parallel, with one equation liying above the y axis, and the other below it.
The question is curiously vague. Do the two lines exist in the same plane? If they do, then they must intersect somewhere -- unless they are parallel. For non-parallel lines, the distance between the two lines at the point of intersection is zero. For parallel lines, the shortest distance between them is the length of the line segment that is perpendicular to both. For intersecting lines, there is an infinite number of distances between the infinite number of pairs of points on the lines. But for any pair of points -- one point on line A and another on line B -- the shortest distance between them will still be a straight line. Given two lines in 3D (space) there are four possibilities # the lines are collinear (they overlap) # the lines intersect at one point # the lines are parallel # the lines are skew (not parallel and not intersecting) The question of "shortest distance" is only interesting in the skew case. Let's say p0 and p1 are points on the lines L0 and L1, respectively. Also d0 and d1 are the direction vectors of L0 and L1, respectively. The shortest distance is (p0 - p1) * , in which * is dot product, and is the normalized cross product. The point on L0 that is nearest to L1 is p0 + d0(((p1 - p0) * k) / (d0 * k)), in which k is d1 x d0 x d1.
The question does not make sense since here is not onlyoone such letter. A, K, M, W, X and Y all have two diagonal straight lines! If your question is "What is the letter with only 2 diagonal lines, then the answer is "V". This letter was omitted by Mr. Mehta.