There are two.
The perfect cubes among the first 1000 natural numbers are the cubes of the integers from 1 to 10, since (10^3 = 1000). These integers are 1, 2, 3, 4, 5, 6, 7, 8, 9, and 10. Therefore, there are 10 perfect cubes in the first 1000 natural numbers.
From 1 to 50, you have the following perfect cubes: 13 = 1 23 = 8 33 = 27 The next perfect cube (43 = 64) is outside the specified range.
The first six perfect cubes are 1, 8, 27, 64, 125, and 216. These correspond to the cubes of the integers 1 through 6, respectively: (1^3 = 1), (2^3 = 8), (3^3 = 27), (4^3 = 64), (5^3 = 125), and (6^3 = 216). Perfect cubes are numbers that can be expressed as the cube of an integer.
The perfect cubes between 10 and 30 are 27, which is the cube of 3 (3^3). The next perfect cube, 64 (4^3), exceeds 30, while the perfect cubes below 10 are 1 (1^3) and 8 (2^3). Therefore, 27 is the only perfect cube in that range.
There are two.
26
1, 8, 27
From 1 to 50, you have the following perfect cubes: 13 = 1 23 = 8 33 = 27 The next perfect cube (43 = 64) is outside the specified range.
The first six perfect cubes are 1, 8, 27, 64, 125, and 216. These correspond to the cubes of the integers 1 through 6, respectively: (1^3 = 1), (2^3 = 8), (3^3 = 27), (4^3 = 64), (5^3 = 125), and (6^3 = 216). Perfect cubes are numbers that can be expressed as the cube of an integer.
Including 1, there are 21 perfect cubes between one and ten thousand. These are: 1, 8, 27, 64, 125, 216, 343, 512, 729, 1000, 1331, 1728, 2197, 2744, 3375, 4096, 4913, 5832, 6859, 8000, 9261.
1,8,27,64,125,216,343,512,729,1000 panghi c bhaby ^_^
1, 8, and 27 are.
Between the two numbers there are only two.
81
The cube root of 5000 is approx 17.1 So the numbers 1 to 17 have cubes which are smaller than 5000 that is, there are 17 such numbers.
Answer: 1, 64, & 729