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How many plate number can be formed consisting of 3 letters in the English alphabet and 3 - digit number no using zero sa first digit and without repetition?
The first part is easy to work out. Each letter can be one of 26. Thus there are 263 possibilities:
263 = 17,576
For the numbers, there are 9 options for the first digit (0 not allowed) then 9 options for the second digit (the first digit not allowed) then 8 options for the third digit (the first two digits not allowed). Thus there are 9x9x8 = 648
To find out the total number of possibilities for combining these elements, you just multiply the numbers together:
17,576 x 648 = 11,389,248
And so there are just over 11 million different plates that can be formed.
What else can I help you with?
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