To find the number of positive integers less than 900 with all odd digits, we consider the digits available: 1, 3, 5, 7, and 9. For a three-digit number, the first digit (hundreds place) can only be 1, 3, 5, 7, or 9 (5 options), while the tens and units places can also be any of the 5 odd digits (5 options each). Thus, there are (5 \times 5 \times 5 = 125) three-digit numbers. For two-digit numbers, the first digit can again be any of the 5 odd digits, and the second digit can also be any of the 5 odd digits, giving (5 \times 5 = 25). Finally, for one-digit numbers, there are 5 options (1, 3, 5, 7, 9). Adding these together gives (125 + 25 + 5 = 155) positive integers less than 900 with all odd digits.
There is only 1, the number 54.
There are none.
49
666 integers.
There are 44 positive integers less than 2,010 that have an odd number of factors.
52
10*9*8=720
There are 20.
There is only 1, the number 54.
There are 870 such numbers.
125
Three of them.
3
20. 16 without repeating a digit.
There are none.
49
666 integers.