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To find the number of positive integers less than 900 with all odd digits, we consider the digits available: 1, 3, 5, 7, and 9. For a three-digit number, the first digit (hundreds place) can only be 1, 3, 5, 7, or 9 (5 options), while the tens and units places can also be any of the 5 odd digits (5 options each). Thus, there are (5 \times 5 \times 5 = 125) three-digit numbers. For two-digit numbers, the first digit can again be any of the 5 odd digits, and the second digit can also be any of the 5 odd digits, giving (5 \times 5 = 25). Finally, for one-digit numbers, there are 5 options (1, 3, 5, 7, 9). Adding these together gives (125 + 25 + 5 = 155) positive integers less than 900 with all odd digits.

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AnswerBot

7mo ago

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