Here are three possible interpretations of the question, with answers:
A) How many combinations are possible when when rolling three identical regular dice simultaneously, if all the dice show an even number?
Answer: 10 (Originally given by Mehta matics)
... (2,2,2) -> 6
... (2,2,4) -> 8
... (2,2,6), (2,4,4) -> 10
... (2,4,6), (4,4,4) -> 12
... (2,6,6), 4,4,6) -> 14
... (4,6,6) -> 16
... (6,6,6)-> 18
B) How many combinations result in an even total when rolling three identical regular dice simultaneously?
Answer:28
... The totals must be between 3 and 18 inclusive.
... sum of 4: (1,1,2)
... sum of 6: (1,1,4), (1,2,3), (2,2,2)
... sum of 8: (1,1,6), (1,2,5), (1,3,4), (2,2,4), (2,3,3)
... sum of 10: (1,3,6), (1,4,5), (2,2,6), (2,3,5), (2,4,4), (3,3,4)
... sum of 12: (1,5,6), (2,4,6), (2,5,5), (3,3,6), (3,4,5), (4,4,4)
... sum of 14: (2,6,6), (3,5,6), (4,4,6), (4,5,5,)
... sum of 16: (4,6,6), (5,5,6)
... sum of 18: (6,6,6), for a total of 1+3+5+6+6+4+2+1 =28 combinations.
C) When rolling three regular dice, how many even totals are possible?
Answer: 8
... 4, 6, 8, 10, 12, 14, 16, 18.
If you have 12 possible numbers with multiple combinations then you should start out with making all the possible combinations; you will find theyre 20. Theyre four numbers out of the twleve that can be divisible by three; 3, 6, 9, and 12. There are 7 combinations where the combinations can equal those four numbers. So the odds of getting a sum divisible by three is 7/20.
When rolling 6 dice, each die has 6 faces, resulting in (6^6) combinations. This calculation yields a total of 46,656 possible combinations. Each combination represents a unique arrangement of numbers from the six dice.
one die, the numbers 1,2,3,4,5 or 6, two dice, the 1,1 1,2 1,3 1,4 1,5 1,6 2,1 etc. There are 36 outcomes
There are 6 possible numbers that can be rolled. "4" is one of those possible numbers. Probability is therefore 1/6.
15/21= 71.43% chance. It's the number of possible throws without repetition divided by the total different combinations of dice throw. Here is a handy Combination and Permutation Calculator: http://www.mathsisfun.com/combinatorics/combinations-permutations-calculator.html
If you have 12 possible numbers with multiple combinations then you should start out with making all the possible combinations; you will find theyre 20. Theyre four numbers out of the twleve that can be divisible by three; 3, 6, 9, and 12. There are 7 combinations where the combinations can equal those four numbers. So the odds of getting a sum divisible by three is 7/20.
one die, the numbers 1,2,3,4,5 or 6, two dice, the 1,1 1,2 1,3 1,4 1,5 1,6 2,1 etc. There are 36 outcomes
There are 6 possible numbers that can be rolled. "4" is one of those possible numbers. Probability is therefore 1/6.
15/21= 71.43% chance. It's the number of possible throws without repetition divided by the total different combinations of dice throw. Here is a handy Combination and Permutation Calculator: http://www.mathsisfun.com/combinatorics/combinations-permutations-calculator.html
The answer is 12 APEX ✨
48
There are 8 possible combinations that would produce a 5 or 9 and 8/36=2/9.
The probability of rolling a 9 with two dice is 4/36 or 1/9. There are 36 possible combinations and a 9 is obtained by rolls of 3,6; 4,5; 6,3; & 5,4.
Of the 36 possible combinations rolling two dice there are 2 combinations that add up to 11 so the odds are 18:1
If the numbers (or symbols) are all different then 10 outcomes.
11 = 6+5 is the only solution, so there are two combinations first dice : 6, second dice : 5 first dice : 5, second dice : 6
The chance is 1/36. (There are 36 possible combinations for two 6-sided dice, but only 18 separate combinations when the dice are not considered seperately.)