In the 6/55 draw it is a choice of 6 out of 55 which is:
55C6 = 55!/6!(55-6)!
= 28,989,675
Just to put it into perspective, using the statistics for the US for 2001 to 2010, the chance of being struck by lightning is about 800,000 to 1 (about 35 times more likely than winning the jackpot), and the chance of dying from being struck about 8,000,000 to 1 (about 31/2 times more likely than winning the jackpot) and yet who wants to be struck, or killed by lightning when they are more likely than winning the jackpot?
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voor lotto 6/42: (42x41x40x39x38x37)/6! = 5.245.786 diffrent combinations posible
458,377,920 for 5 and 21,085,384,320 with the 6th number you need
48
Probably, since there are so many possible combinations. Knowing which one hasn't happened, though, is not useful - the outcome of past random events won't have any future on future random events of the same type. For more details, look for "Gambler's fallacy", in Wikipedia.
I'm not familiar with "Lotto 556", but if it's meaning is the same as "Lotto 649" which I am familiar with, then it means that five unique numbers between 1 and 56 are picked. If that is correct, then the number of winning combinations are: 56! / 51! Which equals: 56 * 55 * 54 * 53 * 52 or: 458377920