The area that 40 pounds of sand will cover at a depth of 1 inch can be estimated based on the density of sand, which is typically around 100 pounds per cubic foot. Since 40 pounds of sand is about 0.4 cubic feet, and 1 inch is ( \frac{1}{12} ) of a foot, the area covered would be approximately 4.8 square feet. Therefore, 40 pounds of sand will cover roughly 4.8 square feet at a depth of 1 inch.
You need to mention how deep you want the sand to be
sand weighs 100 pounds per cubic foot you have 100 x 50 x3/12 cu ft = 1250 cubic feet 1250 x 100 = 125,000 pounds = 125000/2000 = 62.5 tons
100 x 1/4 *1/12 = 2.08 cu ft = about 208 pounds of sand
tweleve
14,300 pounds. Sand has a density of 100 pounds per cubic foot.
No possible answer
You need to mention how deep you want the sand to be
sand weighs 100 pounds per cubic foot you have 100 x 50 x3/12 cu ft = 1250 cubic feet 1250 x 100 = 125,000 pounds = 125000/2000 = 62.5 tons
A 2500 square foot area x 4' deep is 10000 cubic feet. So you need 10,000 cubic feet of sand. Dry sand has a density of 80-100 pounds or so per cubic foot, so that's somewhere between 800,000 and a million pounds of sand.
The volume of sand weighs 455x 2/12 *100 pounds per cubic foot = 7600 pounds so you need about 152 bags.
You need 4.27 cubic feet. Weight in pounds is deceptive for sand depending on how wet or dry the sand is.
100 x 1/4 *1/12 = 2.08 cu ft = about 208 pounds of sand
tweleve
1 yard = 3 feet1 squared yard = 3 square feet
57.6 cu ft
Square yards is a measure of area, you need to purchase your sand as a volume not an area. You will need 2000 cubic feet of sand.