Assume you mean the chord of a circle? If the angle between the two radii from the ends of the chord is A, and the radius of the circle is R, the chord length L will be L = 2RsinA/2. You can prove this easily by joining the point bisecting the chord to the centre, you then have two rightangled triangles, with an included angle of A/2, and an opposite side of L/2. So sinA/2 = L/2R.
First of all , what is 'radi' . If you mean the plural of radius , it is 'RADII'. Note the spelling. It is pronounced as 'ray-dee- eye'. A circle has an infinite number of radii.
Well, the equation for finding the circumfrence of a circle is (diameter)(pi). That is diameter times pi. since the diameter of a circle is 2 radii, we can say that there is 2(pi) radii in a circle.
Yes but a chord cannot be bigger than the circle's diameter which is its largest chord.
Working in degrees, the angle of the greater radius, minus the lesser radius, all over 360, gives the proportion of the area of the circle that is bounded by the radii. This can then be multiplied by the area of the whole circle to give the bounded area.
There are infinite radii in a sphere.
Assume you mean the chord of a circle? If the angle between the two radii from the ends of the chord is A, and the radius of the circle is R, the chord length L will be L = 2RsinA/2. You can prove this easily by joining the point bisecting the chord to the centre, you then have two rightangled triangles, with an included angle of A/2, and an opposite side of L/2. So sinA/2 = L/2R.
A chord is a straight line from one point on a circle's circumference to another. Because the largest straight line distance in a circle is the diameter and the diameter is also a chord, the diameter is the longest chord. Join the endpoints of a given chord to the center of the circle to form an isosceles triangle. The triangle inequality then tells that the length of the chord is less than two radii of the circle, i.e., less than the diameter. See related links.
18.5 million :)
Yes, any diameter which is perpendicular to a chord bisects said chord. This can be proved most easily with a picture, but is proved using a congruent triangle proof. Both triangles include the points at the center of the circle and the intersection of the diameter and chord. The other points should be the endpoints of the chord. They are congruent by hypotenuse leg; it was given that they are right triangle by the "perpendicular", the "leg" is the segment between the center of the circle and the intersection, and it is equal in both triangles because it is the same segment in both triangles. The hypotenuses are equal because both are radii of the circle. Because the triangles are congruent, their sides must be so the two halves of the chord are congruent, and therefore the chord is bisected by the diameter.
Infinitely many.
The plural of 'radius' is 'radii', not 'radiuses'. A circle has an infinite number of radii, but they are all of the same length.
2
Usually there are three notes to make a definable chord.
Assume that the height of the segment is h, the chord length is c and the radius is r then: r2=(r-h)2+(c/2)2 (We join two radii to the two ends of the chord then extend the height of the segment to the center of the circle in which the segment is inscribed so this height will bisect the chord and you use the pythagorean theorem to find the radius)
First of all , what is 'radi' . If you mean the plural of radius , it is 'RADII'. Note the spelling. It is pronounced as 'ray-dee- eye'. A circle has an infinite number of radii.
Well, the equation for finding the circumfrence of a circle is (diameter)(pi). That is diameter times pi. since the diameter of a circle is 2 radii, we can say that there is 2(pi) radii in a circle.