Either +/- 1, and the discriminant will tell. b2 - 4ac
Y = 5X2 - 4 + 1
(- 4)2 - 4(5)(1)
= 16 - 20
= - 4
==========It that 1 is positive then no real roots.
Y = 5x2 - 4 - 1
(- 4)2 - 4(5)(- 1)
16 + 20
= 36
==========if 1 is negative then two real roots.
4
No real roots.
two complex
y = -4x The y-intercept is zero. That is, the graph passes through the origin.
y=x2+4x+1
4
No real roots.
y = x2-4x+4 Since the highest degree term is 2, it must have 2 roots
The y-intercept of the graph of 4x + 2y =12 is probably 6
No real roots. Imaginary roots as this function does not intersect the X axis.
1
two complex
y = -4x The y-intercept is zero. That is, the graph passes through the origin.
Any graph with the slope of -1/2
y = x2 - 4x + 4 = (x - 2)2 has one repeated root
y=x2+4x+1
y=xsquared-4x+2