The equation [ y = x2 - 2x + 5 ] has an infinite number of solutions,
corresponding to every point on the graph of it.
The ROOTS corresponding to the two values of 'x' that satisfy the equation when y=0 ...
in other words, the points where the graph crosses the x-axis.
In the particular case of this equation, the graph doesn't cross the x-axis at all,
and the roots are not real numbers. There are still two of them, and they are
complex conjugates.
The roots are
X = 1 ± 2 i
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2x = 3x + 1; -x = 1; x = -1.
it equals 13X.
many solutions
-2x plus 3y equals 1
X=7