The equation [ y = x2 - 2x + 5 ] has an infinite number of solutions,
corresponding to every point on the graph of it.
The ROOTS corresponding to the two values of 'x' that satisfy the equation when y=0 ...
in other words, the points where the graph crosses the x-axis.
In the particular case of this equation, the graph doesn't cross the x-axis at all,
and the roots are not real numbers. There are still two of them, and they are
complex conjugates.
The roots are
X = 1 ± 2 i
2x = 3x + 1; -x = 1; x = -1.
it equals 13X.
many solutions
-2x plus 3y equals 1
X=7
No real roots
2x = 3x + 1; -x = 1; x = -1.
it equals 13X.
x=1
If you mean y = x^2 -2x +1 then it has two equal roots of 1 when y = 0
many solutions
What is the answer to 2x - 5x plus 6.3 equals -14.4?
-2x plus 3y equals 1
x = 0
1 solution
If Y equals 2X - 2X - 24, then there is one root, and it is -24. The two 2X's cancel each other out.
X=7