For a star shaped figure, as many as the number of points. For a real star (like the ones up in the sky) either infinitely many or none - depending on the level of detail that you look at.
The surface of any star has lots of dimples and bumps caused by stellar activity and these will break up any symmetry. If you ignore these fine details, then the star is a smooth ellipsoid and has infinitely many rotational symmetries.
These symmetries are along the star's axis of rotation. For any other axis, the star's rotation will make the equatorial region bulge out and so there will be no symmetries.
it has 5 rotational symmetry
A star typically has rotational symmetry depending on its number of points. For example, a five-pointed star has five orders of rotational symmetry, meaning it looks the same after a rotation of 72 degrees (360 degrees divided by 5). The number of orders of rotational symmetry is equal to the number of points on the star.
6
Since stars are normally spherical objects, they have rotational symmetry of infinite order.
triangles have 0 rotational symmetry
it has 5 rotational symmetry
A star typically has rotational symmetry depending on its number of points. For example, a five-pointed star has five orders of rotational symmetry, meaning it looks the same after a rotation of 72 degrees (360 degrees divided by 5). The number of orders of rotational symmetry is equal to the number of points on the star.
A sphere has rotational symmetry of an infinite degree.
6
A star
if it is a reg. star, yes it does!:)
Since stars are normally spherical objects, they have rotational symmetry of infinite order.
triangles have 0 rotational symmetry
A parallelogram has a rotational symmetry of 2!
It need not have any, but can have as many as the number of points on the start.
A line has rotational symmetry of order 2.
6 i think.....