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A ordinary year contains 31,536,000seconds.(60x60x24x365)

a leap year contains 31,622,400seconds.

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1.0X 10^12 seconds (1 hour/3600 seconds)(1 day/24 hours)(1 year/365 days) = 31,709.8 years

If the question means:1. How many seconds in one hour andthrity five minutes. And how many seconds in one day5700 seconds for one hour and thirty five minutes.86400 seconds in one day2. How m any hours in one day plus one hour plus thirty five minutes25(60*60) + 35(60)25 (3600) + 210090,000 + 2100 = 92,100 seconds

There are 60 seconds in one minute, 60 minutes in one hour, 24 hours in one day, 14 days in a fortnight. This is a total of 1209600 seconds.

Just like time, 60 seconds are in one minute.

3600 seconds.

Related questions

31536000 seconds

There are 31,536,000 seconds in a normal calender year.

2 months= 5,259,487.66 seconds one year = 31,556,926 seconds !!

9000

In a non-leap year, there are 31536000 seconds in one year.

In a non-leap year, there are 31536000 seconds in one year.

2

60x24x12=17280 seconds

About one (1.005133596978224) year.

There are 31,556,926 seconds in one year. Since there are about 86,400 seconds in one day, multiplied by 365 days in a year, that totals out to about 31,556,926 seconds in a year. 31536000seconds 60sec x 60min x 24hr x 365 days = number of seconds in a calendar year, (31,536,000)

The answer depends on the definition of a year and ranges from 31 556 925 to 31 558 150 seconds.

There are 86,400 seconds in a day and 31,536,000 seconds in a normal year. So, if a leap year is one day longer than a normal year then a leap year would have one more day's worth of seconds. That means that 31,536,000+86,400=the number of seconds in a leap year, or 31,622,400. So there are 31,622,400 seconds in a leap year.^Last post was incorrect^31 556 926 seconds in a year not 31 536 000

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