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The answer is 18C6 which stands for 18!/[6!*(18-6)!] where n! means 1*2*3*...*n.

That simplifies to 18*17*16*15*14*13/(6*5*4*3*2*1) = 18564

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14y ago

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Q: How many sets of 6 numbers in 18 numbers?
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