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It has five of them. Only the interior angles can add up to 540Â°.

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Q: How many sides does a polygon have if its angles add up to 540?

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540o = 6 right angles so 5 sides (interior angles of any polygon = (2 x sides - 4) right angles.

It will have 5 sides and it is a pentagon.

It is a regular pentagon that has 5 sides

Its 5 interior angles add up to 540 degrees

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3

540o = 6 right angles so 5 sides (interior angles of any polygon = (2 x sides - 4) right angles.

It will have 5 sides and it is a pentagon.

It is a regular pentagon that has 5 sides

Where n is the number of sides of a regular polygon, the sum of the internal angles is equal to (n - 2) x 180. In the case of a pentagon, this is equal to (5 - 2) x 180 = 3 x 180 = 540 degrees.Therefore, the number of sides the polygon would have is 5.

Exterior angles 360 degrees Interior angles 540 degrees

The sum of the interior angles (the angles of a polygon is equal to the 180*(n-2), where n is the number of sides. For example, if a polygon has 5 sides the sum of the angles is 180*(5-2), which is 540 degrees.

Its 5 interior angles add up to 540 degrees

We use the formula that the sum is 180(n-2) where n is the number of sides. So 540=180(n-2)540/180-n-23=n-2so n=5 and it is a pentagon.(5 sides)

The sum of the interior angles of any polygon can be determined by using the formula (n-2)180, where n=the number of sides of that polygon. For example, you can calculate the sum of the interior angles of a polygon with five sides (a pentagon): (n-2)180 (5-2)180 3x180 540 So, the sum of the interior angles of a pentagon is 540.

the sum of the interior angles of a 3 sided polygon is = 180 degrees. the sum of the interior angles of any polygon is given by 540/n. in this case n is = 3

Pentagon Degrees=180(n-2) n=# of sides

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