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What is the side of the polygon when the sum of the measures of the vertex angle is 1980 degrees?
If the interior angles of a polygon add up to 1980 degrees then it has 13 sides
What is the sum of the interior angles of a regular polygon with 13 sides?
The sum of interior angles: (13-2)*180 = 1980 degrees
How many sides would a regular polygon have if the sum of exterior angles were 1980 degrees?
The sum of the exterior angles cannot be 1980 degrees - it is always 360 degrees.
What is the sum of the interior angles measure of a 13-polygon?
The sum of the interior angles of any regular polygon of n sides is equal to 180(n - 2) degrees. 1980 degrees.
What is the sum of the interior angle measure of a 13 sides polygon?
The interior angles add up to 1980 degrees.
How many sides does a polygon have if the sum of the interior angles is 1980?
13 sides.
How many sides does a polygon have if the sum of the measures of its angles is 1980 degrees?
13 sides
How many sides does a polygon have when the sum of the measure of its interior angles is 1980?
It will have 13 sides
If the sum of the measures of the interior angles of a polygon is 1980 how many sides does the polygon have?
300
What is the sum of the interior angles of a 13-sides polygon?
1980 degrees
How many sides does a polygon have if its interior angles measure 1980 degrees?
13 of them.
If the sum of the measures of the interior angles of a polygon is 1980 how many sides does it have?
The formula for the sum of the angles of an interior polygon is 180(n-2), where n is the number of sides, so then you solve 180(n-2) = 1980. (n-2) = 11 n = 13. So the polygon has 13 sides.
What is the side of the polygon when the sum of the measures of the vertex angle is 1980 degrees?
If the interior angles of a polygon add up to 1980 degrees then it has 13 sides
If the sum of the measures of the interior angles of a polygon is 1980 degrees how many sides does it have?
The formula for the sum of the angles of an interior polygon is 180(n-2), where n is the number of sides, so then you solve 180(n-2) = 1980. (n-2) = 11 n = 13. So the polygon has 13 sides.
How many sides will a polygon have if the sum of its angles is twenty two right angles?
If the sum of its interior angles is 22*90 which is 1980 degrees then it will have 13 sides Consider the following rules that are applicable to all polygons:- (interior angles+360) divided by 180 = number of sides (number of sides -2) multiplied by 180 = sum of interior angles The above question is rather confusing because it implies that the interior angles of the polygon is the equivalent of twenty two right angles which is the same as 1980 degrees but working out how many sides the polygon has then the same rules apply. (1980+360)/180 = 13 sides (13 -2)*180 = 1980 degrees
What is the sum of the interior angles of a regular polygon with 13 sides?
The sum of interior angles: (13-2)*180 = 1980 degrees
How many sides would a regular polygon have if the sum of exterior angles were 1980 degrees?
The sum of the exterior angles cannot be 1980 degrees - it is always 360 degrees.
