Well, darling, if each small cube has an edge of 10 cm, then the volume of each small cube is 10 x 10 x 10 = 1000 cubic cm. The volume of the big box is 80 x 80 x 80 = 512,000 cubic cm. So, you can fit 512,000 / 1000 = 512 small cubes in that big box. Hope that clears things up, sugar.
1,000 cm3
100
The total volume of two cubes that each have edge lengths of 5 feet is: 250 cubic feet.
Surface area of two cubes = 6 times [ (length of first cube's edge)2 + (length of second cube's edge)2 ]
V = 1,000 cubic centimeters.
If the length of one edge of a cube is 10cm its volume is: 1,000 cm3
Three units on an edge, cubed this would be 27 small cubes to the large cube. There are two cuts in the x, y and z coordinates, so this should be six cuts to go from 27 small cubes to one.
1,000 cm3
100
There are 64 such cubes.
You would need 8 smaller cubes with 2 cm edge to form a larger cube with a 4 cm edge.
The total volume of two cubes that each have edge lengths of 5 feet is: 250 cubic feet.
Surface area of two cubes = 6 times [ (length of first cube's edge)2 + (length of second cube's edge)2 ]
There is only one edge piece on 3x3x3s.
V = 1,000 cubic centimeters.
27 cubes 3x3x3
1 metre = 100 cm so 10 cubes will fit along the length, breadth and height of the box. Therefore 10*10*10 = 1000 cubes will fit.