Well, darling, if each small cube has an edge of 10 cm, then the volume of each small cube is 10 x 10 x 10 = 1000 cubic cm. The volume of the big box is 80 x 80 x 80 = 512,000 cubic cm. So, you can fit 512,000 / 1000 = 512 small cubes in that big box. Hope that clears things up, sugar.
A cubic box with a 1m edge has a volume of (1m^3 = 100cm \times 100cm \times 100cm = 1,000,000cm^3). Each cube with a 10cm edge has a volume of (10cm \times 10cm \times 10cm = 1,000cm^3). To find how many 10cm cubes can fit in the 1m cubic box, divide the volume of the box by the volume of one cube: (1,000,000cm^3 / 1,000cm^3 = 1,000). Therefore, 1,000 cubes of 10cm edge can fit in the cubic box.
1,000 cm3
100
The total volume of two cubes that each have edge lengths of 5 feet is: 250 cubic feet.
Surface area of two cubes = 6 times [ (length of first cube's edge)2 + (length of second cube's edge)2 ]
A cubic box with a 1m edge has a volume of (1m^3 = 100cm \times 100cm \times 100cm = 1,000,000cm^3). Each cube with a 10cm edge has a volume of (10cm \times 10cm \times 10cm = 1,000cm^3). To find how many 10cm cubes can fit in the 1m cubic box, divide the volume of the box by the volume of one cube: (1,000,000cm^3 / 1,000cm^3 = 1,000). Therefore, 1,000 cubes of 10cm edge can fit in the cubic box.
If the length of one edge of a cube is 10cm its volume is: 1,000 cm3
Three units on an edge, cubed this would be 27 small cubes to the large cube. There are two cuts in the x, y and z coordinates, so this should be six cuts to go from 27 small cubes to one.
1,000 cm3
100
There are 64 such cubes.
You would need 8 smaller cubes with 2 cm edge to form a larger cube with a 4 cm edge.
The total volume of two cubes that each have edge lengths of 5 feet is: 250 cubic feet.
Surface area of two cubes = 6 times [ (length of first cube's edge)2 + (length of second cube's edge)2 ]
There is only one edge piece on 3x3x3s.
V = 1,000 cubic centimeters.
27 cubes 3x3x3