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However, it appears as if the given equations are inconsistent (parallel lines) and so have no solution.
3x-3y
3x-2y=24 (1)6x-4y=-6 (2)(1) => 6x-4y=48 [(1)*2](1)*2=(2)therefore:6x-4y = -6 AND 48-6 ≠ 48the equation cannot be solved
None because without an equality sign it can't be considered to be an equation
We will see. 3X + 2Y = 15 6X + 4Y = 30 I do not like the look of elimination, so substitution 3X + 2Y = 15 3X = 15 - 2Y X = 5 - 2/3Y -------------- 6(5 - 2/3Y) + 4Y = 30 30 - 12/3Y = 30 30 - 4Y = 30 this is inconsistent in approach 3(5 - 2/3Y) + 2Y = 15 15 - 15/3Y = 15 another bad approach, try elimination to show inconsistency - 2(3X + 2Y = 15) 6X + 4Y + 30 -6X - 4Y = - 30 6X + 4Y = 30 I think it is safe to say these systems of equations are inconsistent --------------------
2p = 4y - 12xy - 6x, 3q = 12 - 15y so 2p - 3q = 4y - 12xy - 6x - (12 - 15y) = 4y - 12xy - 6x - 12 + 15y = 19y -12xy - 6x - 12
(6x - 5y) + (-3x - 4y) =6x - 5y - 3x - 4y =3x - 9y =3 (x - 3y)
3x-3y
3x-2y=24 (1)6x-4y=-6 (2)(1) => 6x-4y=48 [(1)*2](1)*2=(2)therefore:6x-4y = -6 AND 48-6 ≠ 48the equation cannot be solved
None because without an equality sign it can't be considered to be an equation
-2
If you mean: 3x-2y = -2 and 6x-4y = 0 then they are parallel lines having the same slope or gradient of 1.5
14
We will see. 3X + 2Y = 15 6X + 4Y = 30 I do not like the look of elimination, so substitution 3X + 2Y = 15 3X = 15 - 2Y X = 5 - 2/3Y -------------- 6(5 - 2/3Y) + 4Y = 30 30 - 12/3Y = 30 30 - 4Y = 30 this is inconsistent in approach 3(5 - 2/3Y) + 2Y = 15 15 - 15/3Y = 15 another bad approach, try elimination to show inconsistency - 2(3X + 2Y = 15) 6X + 4Y + 30 -6X - 4Y = - 30 6X + 4Y = 30 I think it is safe to say these systems of equations are inconsistent --------------------
parallel
We can certainly simplify that term. 6x - 3x = 3x. And -4y + y = -3y. So the simplified expression is 3x-3y. You could also call this 3(x-y). That's as far as we can go, since we have no way to evaluate x or y without further information.
2p = 4y - 12xy - 6x, 3q = 12 - 15y so 2p - 3q = 4y - 12xy - 6x - (12 - 15y) = 4y - 12xy - 6x - 12 + 15y = 19y -12xy - 6x - 12
They are parallel straight lines,