answersLogoWhite

0


Best Answer

The area of a circle is πr2 where π=3.14159 (approx) and r = radius of the circle. So 3.14159 x 8 x 8 = 201.06193 square inches.

User Avatar

Wiki User

7y ago
This answer is:
User Avatar
More answers
User Avatar

Wiki User

9y ago

The answer depends on 16 WHAT! Please resubmit with the relevant information.

This answer is:
User Avatar

Add your answer:

Earn +20 pts
Q: How many square inches are in a 16 circle?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Related questions

How many square inches in a 16 inch Diameter circle?

201.06


What is the area of a circle with diameter of 16 inches?

The area of a circle with diameter of 16 inches is: 201.1 square inches.


Where is the area on a circle with a diameter of 16 inches?

The area of a circle with a diameter of 16 inches is: 201.1 square inches.


What is the area of the circle if the diameter is 16 inches?

The area of the circle if the diameter is 16 inches is: 201.1 square inches.


What is the area of a circle with a diameter of 16 inches?

The area of a circle with a diameter of 16 inches is: 201.1 square inches.


What is the area of a circle 16 inches in diameter?

A 16-inch circle has an area of 201.06 square inches.


How many square inches are in 16 inches diameter circle?

Area of a circle = pi R2R = radius = 1/2 diameter.For diameter = 16 inches, Area = pi (8)2 = 64 pi = 201.1 square inches (rounded)


How many square inches in a 6.5 inch diameter circle?

radius = ½ diameter area circle = π × radius² = π × (½ × 6.5 in)² = 169π/16 in² ≈ 33.2 in²


4 inches times 4 inches equals how many square inches?

4 inches by 4 inches equals 16 square inches. Each side has a length of 4 inches, and when multiplied together, the area is 16 square inches.


What is the area of a circle with a diametrer of 16 in?

201.06 square inches.


What is the area of a 16 inch circle?

201 square inches.


What is the area of a circle if it has a diameter which is 16 inches long?

The area is 201.1 square inches.