It is easy to show this graphically but, given the limitations of this browser, an algebraic explanation is the best that I can do.
Suppose the sides of the square are x inches.
Then, by Pythagoras, the diameter is sqrt(x2 + x2) = sqrt(2x2) = x*sqrt(2) inches
ie x*sqrt(2) = 10 or x = 10/sqrt(2) = 5*sqrt(2)
Then area = x2 = 25*2 = 50 square inches.
19.63 square inches are in the area of a 5-inch diameter circle.
The area of a 3-inch diameter circle is about 7.068 square inches.
The area of a circle with an 8 inch diameter is approximately 50.27 square inches.
There are 100*pi square inches in a 20 inch diameter circle
A circle whose diameter is 2 inches has an area of 'pi' square inches.3.142 in2 (rounded)
A 4.75-inch diameter circle contains 17.72 square inches.
19.63 square inches are in the area of a 5-inch diameter circle.
The area of a 3-inch diameter circle is about 7.068 square inches.
The area of a circle with an 8 inch diameter is approximately 50.27 square inches.
There are 100*pi square inches in a 20 inch diameter circle
A 1.25-inch diameter circle contains 1.227 square inches.
70.9 square inches.
A 20-inch diameter circle contains: 314.16 square inches.
Area = (pi) x (1/2 of the diameter)2 11-inch diameter ==> 95.033 square inches of area (rounded)
A circle whose diameter is 2 inches has an area of 'pi' square inches.3.142 in2 (rounded)
113.04 if the diameter is twelve inches
A circle with a 23 inch diameter has am area of 415.4756 sq inches (to 4 dp).