36 sq inches.
To determine how many 3x9 inch tiles are needed for 80 square feet, first convert the tile dimensions to square feet. Each tile measures 3 inches by 9 inches, which is 27 square inches. There are 144 square inches in a square foot, so each tile covers 27/144 = 0.1875 square feet. To cover 80 square feet, you would need 80 / 0.1875 = approximately 427 tiles.
A 2 square foot area is equivalent to 288 square inches (since 1 square foot equals 144 square inches). Each 3 inch by 3 inch tile covers 9 square inches. Therefore, to find the number of tiles that can fit, divide the total area by the area of one tile: 288 square inches ÷ 9 square inches per tile = 32 tiles. So, 32 tiles can fit in a 2 square foot area.
A 4 inch by 4 inch tile is 16 square inches. 60 square feet is 8640 square inches. Dividing the one by the other shows us that 540 tiles 4 inches on a side will cover an area of 60 square feet.
18 inches is equal to 1.5 feet.Therefore the area is 1.52 = 2.25 square feet.
To determine how many 16-inch by 16-inch tiles are needed to cover 84 square feet, first convert the tile size to square feet. Each tile is 16 inches by 16 inches, which is 1.33 feet by 1.33 feet, resulting in approximately 1.78 square feet per tile. Next, divide 84 square feet by 1.78 square feet per tile, which equals about 47.2. Therefore, you would need 48 tiles to cover 84 square feet.
There are 1.5 times 3 = 4.5 square feet in an 18 inch by 36 inch tile. 18 inches = 1.5 feet (since there are 12 inches in a foot). 36 inches is 3 feet. The area of a rectangular tile is the width x height, so 1.5 x 3 = 4.5 square feet.
To determine how many 3x9 inch tiles are needed for 80 square feet, first convert the tile dimensions to square feet. Each tile measures 3 inches by 9 inches, which is 27 square inches. There are 144 square inches in a square foot, so each tile covers 27/144 = 0.1875 square feet. To cover 80 square feet, you would need 80 / 0.1875 = approximately 427 tiles.
Each tile covers 336 square inches. You have 62,208 square inches to cover. You will need 185.1 tiles, plus extra for damage and shaping.
A 4 inch by 4 inch tile is 16 square inches. 60 square feet is 8640 square inches. Dividing the one by the other shows us that 540 tiles 4 inches on a side will cover an area of 60 square feet.
A square 20-inch tile is 2.78 square feet.
18 inches is equal to 1.5 feet.Therefore the area is 1.52 = 2.25 square feet.
To determine how many 16-inch by 16-inch tiles are needed to cover 84 square feet, first convert the tile size to square feet. Each tile is 16 inches by 16 inches, which is 1.33 feet by 1.33 feet, resulting in approximately 1.78 square feet per tile. Next, divide 84 square feet by 1.78 square feet per tile, which equals about 47.2. Therefore, you would need 48 tiles to cover 84 square feet.
The perimeter would be 4 inches !
One 9 inch square tile would presumably be 9in x 9in or 81in2, unless you are meaning 3in x 3in tile which is then 9in2. Regardless, the answer to your question is the total area of the floor (in square inches) divided by the total area of one tile (in square inches).
The area of each tile is 16*16 sq inches = 1.77... square feet. To cover a 200 square foot square will require 200/1.77... = 112.50 = 113 tiles.
1070 square feet is 154080 square inches. (1 square foot is 12x12 or 144 square inches.)a 20x20 inch tile is 400 square inches.So the question could be restated as "how many 400 square inch tiles does it take to cover 154080 square inches?"154080 / 400 = 385.2
This tile has an area of 1 ft2.