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How many different 9-member teams can be chosen from 12 students?

To determine how many different 9-member teams can be chosen from 12 students, we can use the combination formula ( C(n, k) = \frac{n!}{k!(n-k)!} ). Here, ( n = 12 ) and ( k = 9 ). This can also be expressed as ( C(12, 9) = C(12, 3) ), which simplifies the calculation. Thus, ( C(12, 3) = \frac{12!}{3! \cdot 9!} = \frac{12 \times 11 \times 10}{3 \times 2 \times 1} = 220 ). Therefore, there are 220 different 9-member teams that can be formed.


How many ways can a group of 12 including 7 boys and 5 girls be formed into two 5 person teams so each team has more than one girl?

5


How many 2 digit numbers can be formed 6987?

12


How many ways can a group of 12 including 4 boys and 8 girls be formed into two 6 person volleyball teams with no restrictions?

462 waysExplanationIn the question, it does not seem to matter how many boys or girls are on a team. So really you are asking how many ways are there to divide 12 people into two teams of 6.The answer is (12C6)/2 where 12C6 means 12 choose 6First 12 chose 6 is 12!/(12-6)!(6)! which is 12x11x10x9x8x7x6x5x4x3x2x1/(6x5x4x3x2x1)(6x5x4x3x2x1)=(12x11x10x9x8x7)/(6x5x4x3x2x1)=924(As a side note, the Google browser will calculate these numbers if you just type in 12 choose 6, for example)Now once one team of 6 is chosen, the other team is automatically the remaining 6 so we have really double counted. That is why we divide by 2 and the answeris 462 ways.


How many 4 person can be chosen from a pool of 12 people?

To determine how many groups of 4 can be chosen from a pool of 12 people, you can use the combination formula, which is ( C(n, r) = \frac{n!}{r!(n-r)!} ). Here, ( n = 12 ) and ( r = 4 ). This gives ( C(12, 4) = \frac{12!}{4!(12-4)!} = \frac{12!}{4!8!} = 495 ). Thus, 495 different groups of 4 people can be formed from the pool of 12.