The counting principle works like this.
Multiply the number of choices you have for each character.
If you can have 0000000000 then you would multiply 10x10x10x10x10x10x10x10x10x10 or 10,000,000,000.
10 billion.
If you eliminate that number that there is one less.
How many times does the digit 1 occur in ten place in the numbers from 1 to 1000?
81
That would be the numbers in the form "32x" (where "x" can be any digit). In other words, ten numbers.
ten
Technically, that is not possible. A digit is another word for a number and it would be impossible for a single number to contain ten numbers.
How many times does the digit 1 occur in ten place in the numbers from 1 to 1000?
Ten.
81
2
ten factorial = 10! = 3,628,800
The product of the ten one-digit numbers is 0.
France does not have area codes - they have ten digit phone numbers that are dialled in full. Numbers starting '02' are normally in north west France.
There are 9000 4 digit numbers Find 4 digit numbers that are all different from 1 find 4 digit numbers that are all different from 1 The thousands digit has 8 ways to choose, hundreds, tens, and units all have 9 ways => there are 8 x 9 x 9 x 9 = 5832 digits => 4 digit numbers contain at least 1 digit 1 = number of 4 digit numbers , the number of 4 digit numbers is different by digit 1 =9000 - 5832 = 3168 numbers
In base ten, there are 9000 four digit number, the numbers are from 1000 to 9999. If you allow leading zeros, then there are 10000 numbers. [0000 - 9999]
That would be the numbers in the form "32x" (where "x" can be any digit). In other words, ten numbers.
ten
zero