19 times
ten times
11
20 times if you're counting by ones.
This is a very ambiguous question. First, by "writing down from 50 to 100" I presume you mean writing down all the whole numbers from 50 to 100 inclusive, that is, including 50 and including 100. Now, if by "how many times will 10 occur" you mean how many of those numbers will be multiples of 10, the answer is 6. If you mean how many times will the 2 digits 1 and 0 occur in that order as consecutive digits in the decimal numeral of a number, the answer is 1 (100 is the only one of those 51 numerals that contains the digit 1 followed by 0).
19 times
20 times
ten times
20
11
20 times if you're counting by ones.
This is a very ambiguous question. First, by "writing down from 50 to 100" I presume you mean writing down all the whole numbers from 50 to 100 inclusive, that is, including 50 and including 100. Now, if by "how many times will 10 occur" you mean how many of those numbers will be multiples of 10, the answer is 6. If you mean how many times will the 2 digits 1 and 0 occur in that order as consecutive digits in the decimal numeral of a number, the answer is 1 (100 is the only one of those 51 numerals that contains the digit 1 followed by 0).
The number 7 occurs once. The digit 7 occurs 20 times.
100/1 = 100 Therefore, 100 is 100 times larger than 1.
That looks like it should be the same as 10 times (the number of times the digit 1 occursin the units place in the numbers from 10 to 100), which would work out to 90 .
How many times does the digit 1 occur in ten place in the numbers from 1 to 1000?
100