Q: How many times as great is the underlined digit 5 in 365485201 than the digit 5 that is not underlined?

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how many times as great is the underlined 4 as the 8 that is not underlined? 643 234

10 000

4000000 / 4000 = 1000

I guess the underlined 5 is the first one and the non-underlined 5 is the second. Every times a digit moves left a column it becomes ten times bigger. The first 5 is three columns to the left of the second 5, so it is 10 x 10 x 10 = 1000 (a thousand) times bigger. If the underlined 5 is the second one, then in moving right a column a digit becomes one tenth as big, so in moving right 3 columns it becomes 1/10 x 1/10 x 1/10 = 1/1000 (a thousandth) as big, that is the second 5 would be a thousand times smaller than the first 5.

4 times

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34,864,753...... 4 millions is the underlined digit....

how many times as great is the underlined 4 as the 8 that is not underlined? 643 234

how many times as great is the underlined 4 as the 8 that is not underlined? 643 234

how many times as great is the underlined 4 as the 8 that is not underlined? 643 234

10 000

It's either 1 million times as great or 1 millionth as great. The ambiguity is due to the fact that I can't see the underline.

4000000 / 4000 = 1000

ten thousand

I guess the underlined 5 is the first one and the non-underlined 5 is the second. Every times a digit moves left a column it becomes ten times bigger. The first 5 is three columns to the left of the second 5, so it is 10 x 10 x 10 = 1000 (a thousand) times bigger. If the underlined 5 is the second one, then in moving right a column a digit becomes one tenth as big, so in moving right 3 columns it becomes 1/10 x 1/10 x 1/10 = 1/1000 (a thousandth) as big, that is the second 5 would be a thousand times smaller than the first 5.

4 times

It is 10 to the power of the_number_of_digits_between_the_4s_(excluding_the_4s_themselves)_plus_one; if the underlined 4 is to the right of the non-underlined 4, then make this count negative.eg, if the number is 1234564, then there are 2 digits between them (the 5 and 6), so the power is 2 + 1 = 3; then:If the first 4 is underlined it is 103 = 1000 times greater than the non-underlined 4If the second 4 is underlined it is 10-3 = 0.001 (= 1/1000) times greater than the non-underlined 4

great effort