Well, isn't that a lovely little math question! Let's see, if we take 15 and divide it by 8, we find that 8 can go into 15 one time with a remainder of 7. It's all about finding the beauty in the numbers and enjoying the process of solving the problem. Remember, there are no mistakes in math, just happy little accidents!
8 times
To determine how many times 15 can go into 130, you would perform division. When you divide 130 by 15, you get 8 with a remainder of 10. Therefore, 15 can go into 130 exactly 8 times with a remainder of 10.
15.5solve: 8/124-80-40- -4____________0
40/15 = 8/3
15 with remainder 3.
8 times
15, with 5 left over.
To determine how many times 8 will go into 120, you divide 120 by 8. The result is 15, meaning that 8 will go into 120 15 times without a remainder. This is because 8 multiplied by 15 equals 120.
To determine how many times 15 can go into 130, you would perform division. When you divide 130 by 15, you get 8 with a remainder of 10. Therefore, 15 can go into 130 exactly 8 times with a remainder of 10.
38 ÷ 15 = 2 with remainder 8
15.5solve: 8/124-80-40- -4____________0
134 ÷ 15 = 8 with remainder 14
56
32.5
15 times since 120 divided by 8=15 or 15x8=120
143/15 = 9 remainder 8
40/15 = 8/3