Only once - thanks to the unique prime factorisation theorem.
Yes! 2 times 5 equals 10. 10 times 3 equals 30. So, the prime numbers that multiply together to make 30, are, 2, 3 and 5.
The prime factorization of 225 is (3^2 \times 5^2). To express this as a product of four prime numbers, we can write it as (3 \times 3 \times 5 \times 5). Thus, the four prime numbers that multiply to make 225 are 3, 3, 5, and 5.
They are: 7 times 13 = 91
The four prime numbers that multiply together to make 945 are 3, 3, 5, and 7. Specifically, the prime factorization of 945 is (3^2 \times 5 \times 7). Thus, the unique prime factors involved are 3, 5, and 7.
The prime factorization of 105 is (3 \times 5 \times 7). To express this as a product of four prime numbers, we can include 1 as a prime number (though technically, 1 is not prime), yielding the combination (1 \times 3 \times 5 \times 7 = 105). However, if strictly considering only primes, the prime factors are 3, 5, and 7, which multiply to give 105. Therefore, there are not four distinct prime numbers that multiply to make 105.
You can multiply 2 times 11 times 5 to make 110! (2x11=22x5=110)
Three times three times three.
Yes! 2 times 5 equals 10. 10 times 3 equals 30. So, the prime numbers that multiply together to make 30, are, 2, 3 and 5.
They are: 7 times 13 = 91
The prime factorization of 225 is (3^2 \times 5^2). To express this as a product of four prime numbers, we can write it as (3 \times 3 \times 5 \times 5). Thus, the four prime numbers that multiply to make 225 are 3, 3, 5, and 5.
The four prime numbers that multiply together to make 945 are 3, 3, 5, and 7. Specifically, the prime factorization of 945 is (3^2 \times 5 \times 7). Thus, the unique prime factors involved are 3, 5, and 7.
The prime factorization of 105 is (3 \times 5 \times 7). To express this as a product of four prime numbers, we can include 1 as a prime number (though technically, 1 is not prime), yielding the combination (1 \times 3 \times 5 \times 7 = 105). However, if strictly considering only primes, the prime factors are 3, 5, and 7, which multiply to give 105. Therefore, there are not four distinct prime numbers that multiply to make 105.
43 is a prime number. So, 43 can only be produced as a product of 1 times 43.
The prime factorization of 735 is (3 \times 5 \times 7 \times 7). However, since 7 is repeated, it does not constitute four distinct prime numbers. The four prime numbers that multiply to give 735, including repetition, are 3, 5, and two instances of 7. Thus, the prime numbers are 3, 5, 7, and 7.
Yes, this is called their prime factorization.
To multiply two numbers together.
They are: 1 times 19 = 19 which is a prime number