Q: What is the probability of drawing three jacks in a row if the card is replaced after each draw?

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The probability of drawing two jacks and three tens of any suite from a standard deck of cards is: 5C2 ∙ (4/52)∙(3/51)∙(4/50)∙(3/49)∙(2/48) = 0.00000923446... ≈ 0.0009234% where 5C2 = 5!/[(5-2)!∙(2!)] = 10

The probability of drawing the first face card is 12 in 52. The probability of drawing the second is 11 in 51. The probability of drawing the third is 10 in 50. Thus, the probability of drawing three face cards is (12 in 52) times (11 in 51) times (10 in 50) or (1320 in 132600) or about 0.009955.

There are 12 face cards and three of them are hearts. Therefore, the probability of drawing a face card that is heart is 3/12 = 1/4. The probability of drawing a face card that is not a heart is 1-1/4 = 3/4.

The probability of drawing three aces from a deck of cards is 1 in 5525. The probability of the first ace is 4 in 52, or 1 in 13. The second ace is 3 in 51, or 1 in 17. The third ace is 2 in 50, or 1 in 25. Multiply these three probabilities together and you get 1 in 5525.

52 cards in a pack. 4 two's, 4 three's, hence 8 chances of drawing one of the desired cards out of the 52. 8/52 = 2/13

Related questions

The probability of drawing two jacks and three tens of any suite from a standard deck of cards is: 5C2 ∙ (4/52)∙(3/51)∙(4/50)∙(3/49)∙(2/48) = 0.00000923446... ≈ 0.0009234% where 5C2 = 5!/[(5-2)!∙(2!)] = 10

The probability of drawing aces on the first three draws is approx 0.0001810

The probability of drawing the first face card is 12 in 52. The probability of drawing the second is 11 in 51. The probability of drawing the third is 10 in 50. Thus, the probability of drawing three face cards is (12 in 52) times (11 in 51) times (10 in 50) or (1320 in 132600) or about 0.009955.

The probability of A is denoted P(A) and the probability of B is denoted P(B). P(A or B) = P(A) + P(B) - P(A and B). Say P(A) = Probability of drawing a heart, which is 13/52. Say P(B) = Probability of drawing a three, which is 4/52. We now have to determine P(A and B) which is the probability of a heart and a three, which is 1/52. We now can determine the probability of drawing a heart or a three which is 13/52 + 4/52 - 1/52 = 16/52 = 4/13.

The probability of drawing three black cards from a standard pack depends on:whether the cards are drawn at random,whether or not the drawn cards are replaced before the next card is drawn,whether the probability that is required is that three black cards are drawn after however many draws, or that three black cards are drawn in a sequence at some stage - but not necessarily the first three, or that the first three cards cards that are drawn are black.There is no information on any of these and so it is not possible to be certain about the answer.The probability of drawing three black cards, in three random draws - without replacement - from a standard deck, is 0.1176 approx.

The answer is 1/169.

The probability of drawing three black cards one at a time with replacement from a standard deck of 52 cards is 1/3x1/2x26/52, which is 0.833.

There are 12 face cards and three of them are hearts. Therefore, the probability of drawing a face card that is heart is 3/12 = 1/4. The probability of drawing a face card that is not a heart is 1-1/4 = 3/4.

The probability of drawing two blue cards froma box with 3 blue cards and 3 white cards, with replacement, is 1 in 4, or 0.25.The probability of drawing one blue card is 0.5, so the probability of drawing two is 0.5 squared, or 0.25.

If an event has a probability of 1, it will happen no matter what. The probability of rolling a number x, such that 1 ≤ x ≤ 6, on a standard 6 sided die, is 1. The probability of the temperature being > absolute 0, is 1. With a standard 52 card deck of card, P(drawing a spade or drawing a club or drawing a heard or drawing a diamond) is 1. In these situations, there is no variable that can affect the event. It will happen no matter what.

The probability of drawing the first ace is 4 in 52. The probability of getting the second ace is 3 in 51. The probability of getting the third ace is 2 in 50. The probability, then, of drawing three aces is (4 in 52) times (3 in 51) times (2 in 50), which is 24 in 132600, or 1 in 5525, or about 0.0001810

Red cards will be a 1/3 chance to pick out of three cards .