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Period ( left swing + right swing) of a simple pendulum = 2*pi * sqrt (L/g) in seconds.

g = 32.2 feet per second2

L = 32 inches = 2.66667 feet

Period = 2*pi * sqrt ( 2.66667ft/32.2) = 2*pi * 0.287777 = 1.808158 seconds for one period (two swings).

Periods in one minute = 60 sec / 1.808158 sec = 33.183 periods in one minute.

Times 2 = 66.366 swings in one minute.

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Q: How many times does a 32 inch pendulum swing in one minute?
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