100 / 10 = 10.
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There is no four digit number where the ones is twice the tens, the hundreds is five less than the ones, and the thousands is the sum of the tens and hundreds. int ones, tens, hundreds, thousands; for (thousands=1; thousands<10; thousands++) { /**/ for (hundreds=0; hundreds<10; hundreds++) { /**/ /**/ for (tens=0; tens<10; tens++) { /**/ /**/ /**/ for (ones=0; ones<10; ones++) { /**/ /**/ /**/ /**/ if (ones != 2 * tens) break; /**/ /**/ /**/ /**/ if (hundreds != ones - 5) break; /**/ /**/ /**/ /**/ if (thousands != tens + hundreds) break; /**/ /**/ /**/ /**/ printf ("dd\n", thousands, hundreds, tens, ones); /**/ /**/ /**/ } /**/ /**/ } /**/ } }
First, calculate the product of 53 hundreds and 60 tens: (53 \times 100 \times 60 \times 10 = 53 \times 6000 = 318000). To find how many thousands are in 318,000, divide by 1,000: (318,000 \div 1,000 = 318). Therefore, there are 318 thousands in the product of 53 hundreds and 60 tens.
In the number 4553, the 5 in the hundreds place represents 500, while the 5 in the tens place represents 50. To find how many times bigger the 5 in the hundreds place is than the 5 in the tens place, you divide 500 by 50, which equals 10. Therefore, the 5 in the hundreds place is 10 times bigger than the 5 in the tens place.
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