13 R 1
3
40 times.
3 times with a remainder of 24 or 3.6 times
The answer is 13 with remainder 1, or 13⅓ = 13.3 recurring.
3 times with a remaider of 29
Exactly 40 times
4 times with a remainder of 3
To determine how many times 40 can go into 136, you would perform a division operation. When you divide 136 by 40, the result is 3 with a remainder of 16. This means that 40 can go into 136 three times, with 16 remaining.
40/15 = 8/3
85 can go into 255 3 times.
3 with remainder 7.
4.075 times or 4 with remainder 3.